Given:
A cylindrical container closed of both end has a radius of 7cm and height of 6cm.
Explanation:
A.) Find the total surface area of the container.
- A = 2πrh + 2πr²
- A = 2(3.14)(7)(6) + 2(3.14)(7 × 7)
- A = 263.76 + 307.72
- A = 571.48
B.) Find the volume of the container.
- V = πr²h
- V = (3.14)(7×7)(6)
- V = 923.16
Not sure huhuness.
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Answer:
The speed of the block is 4.96 m/s.
Explanation:
Given that.
Mass of block = 1.00 kg
Spring constant = 500 N/m
Position 
Coefficient of friction = 0.350
(A). We need to calculate the speed the block has as it passes through equilibrium if the horizontal surface is friction less
Using formula of kinetic energy and potential energy
Put the value into the formula
Hence, The speed of the block is 4.96 m/s.
Responder:
Fy = 2474,8737
Fx = 2474,8737
Explicación:
Dado que :
Dado:
Fuerza, F = 3500 N
Ángulo formado con la horizontal, θ, = 45 °
Los componentes de una fuerza se pueden descomponer en componentes verticales y horizontales.
El componente vertical Fy; y
El componente horizontal Fx
Fy = Fuerza * sinθ
Fy = 3500 * sin45 °
Fy = 2474,8737
El componente horizontal:
Fx = Fuerza * cosθ
Fy = 3500 * cos45 °
Fy = 2474,8737
Answer:
0.159
Explanation:
the formula to find its is 1÷2*gt^2
Answer:
Δx=(v+v0/2)t
Explanation:
We can figure out which kinematic formula to use by choosing the formula that includes the known variables, plus the target unknown.
In this problem, the target unknown is the initial velocity v_0v
0
v, start subscript, 0, end subscript of the roller coaster.
