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2 years ago

How many triangles can be made with the lengths 4 centimeters 2 centimeters and 7 centimeters

1 answer:

4 0

None, because you must add the 2 shortest sides and the total must be greater than the longest side in order to be able to make a triangle.

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Why is math so hard

sergeinik [125]

Cause it's already hard thou
Hope this help hahahahaha

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2 years ago

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Jack's average in math for the first nine week was an 88. His second nine weeks average decreased 12.5 . What was his average fo

pashok25 [27]

The answer is that his average is 75.5 for the second nine weeks

5 0

2 years ago

Find the cost of carpeting a 9 foot by 12 foot room at $30 per square yard.

S_A_V [24]

Area = length X width
A = L(12 ft) x W(9 ft) but since the cost of carpet is given in square yards not square feet we need to convert
A = (12 ft)(1 yd/3 ft) x (9 ft)(1 yd/3 ft) 1 yard = 3 feet so 1 foot = 1/3 yard
A = 4 yd x 3 yd divide by 3 ft which cancels the original ft and leaves yd's
A = 12 square yards
Cost = Area x price per yard
Cost = 12 sq yd X $35.00/ sq yd multiply and the sq yd's cancel leaving just cost in dollars
Cost = $420.00

8 0

1 year ago

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g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

2 years ago

Find the volume of the figure below. Round your answer to the nearest hundredth if necessary.

slamgirl [31]

Answer:

C. 225 km3

Step-by-step explanation:

7 0

2 years ago