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ArbitrLikvidat [17]
3 years ago
15

I need help plz thxzzz

Mathematics
2 answers:
uysha [10]3 years ago
8 0
I will help u but i cant really see what the pic is so can u copy and paste the question on here.
Nonamiya [84]3 years ago
4 0
Hmm... I am not 100% sure but I think the original price was $375
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What is 64x64? and I know if you use a calculator =)
Savatey [412]

Answer:

4096

Step-by-step explanation:

7 0
3 years ago
If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

10x - 11 = 8x + 23

Subtract 8x from both sides

10x - 11 - 8x = 8x + 23 - 8x

2x - 11 = 23

Add 11 to both sides

2x - 11 + 11 = 23 + 11

2x = 34

Divide both sides by 2

\frac{2x}{2} = \frac{34}{2}

x = 17

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0
3 years ago
What is the solution to the system of equations?
Dvinal [7]
X = 4
y = 0
is the answer to the system of equation
8 0
3 years ago
Plz help me !!!!!!!!
vazorg [7]

You factor the numerator and denominator and cancel the common factors. So maybe that should help you

8 0
3 years ago
Read 2 more answers
A teacher collects data on the number of hours, s, his students spend studying and the number of hours, t, they spend watching T
Sidana [21]
Since there is a negative correlation, evident by the negative slope of the equation of the line given to be -0.5, if we take t as 0, we get an equation of,
                                            s = 3.6
This means that if a student does not watch television, he or she spends a maximum of 3.6 hours studying. 
5 0
3 years ago
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