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3 years ago

I need help plz thxzzz

Mathematics

2 answers:

uysha [10]3 years ago

8 0

I will help u but i cant really see what the pic is so can u copy and paste the question on here.

Nonamiya [84]3 years ago

4 0

Hmm... I am not 100% sure but I think the original price was $375

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Which statement about the polygons is true?

tatyana61 [14]

Polygon A is similar to Polygon B because Polygon B is a dilation of Polygon A.

6 0

3 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

3 years ago

The x-intercepts of a quadratic function are −3 and 5. What is the equation of its axis of symmetry?

Reil [10]

Answer:

x = 1

Step-by-step explanation:

Remember that the axis of symmetry is exactly halfway between the x-intercepts. Find the average of -3 and 5 to obtain this x-value: It is:

-3 + 5

x - intercept = ------------ = x = 1

4 0

3 years ago

If the sum of six consecutive even integers is 390 what is the smallest of the six integers

saveliy_v [14]

The answer is 60 but im going to explain it down below if you want to know how to do it :)

first because we dont know the values of the 6 numbers we have to lay it out like this.
x
x+2
x+4
x+6
x+8
x+10
-------- (then we add it together)
6x+30 = 390 (the sum of the 6 numbers)

using this equation we find out what x is

so we do 390-30 to find what 6x is, which is 360
because now we know that 6x=360, we divide 360 by 6 to find out what x is
360 divided by 6 =60..... x = 60

so now we know that the smallest integer is 60
to check the answer we could add the 6 numbers which are:
60+62+64+66+68+70=390 :)

so the smallest integer is 60

5 0

3 years ago

P = 2L + 2W; for L NEED HELP PLEASE

Orlov [11]

L=(P-2W)/2 HOPE I HELPED YA :)

3 0

3 years ago