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dem82 [27]
3 years ago
5

I need to know how to answer this if someone could explain it step by step thanks!

Mathematics
1 answer:
vlada-n [284]3 years ago
7 0

Step-by-step explanation:

2 \sqrt{7x} .3 \sqrt{14 {x}^{2} }  \\  = 2 \times 3 \sqrt{7x \times 14 {x}^{2} }  \\  = 6 \sqrt{7x  \times 2 \times 7 {x}^{2} }  \\  = 6 \sqrt{2 \times 7 \times 7 \times  {x}^{2} \times x }  \\  = 6 \times 7 \times x \sqrt{2 \times x}  \\  = 42x \sqrt{2x}

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Given

3y³ = 2x⁹ + 1

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We need to first find dy/dx which is the first derivative and then d²y/dx² which is the second derivative

\frac{dy}{dx} = \frac{2x^8}{y^2}

\frac{d^{2}y }{dx^2} = \frac{16x^7}{y^2} - \frac{8x^1^6}{y^5}

Put the value of (1,1) : x = 1 and y = 1 in d²y/dx² equation

\frac{d^2y}{dx^2}  = \frac{16 X 1^7}{1^2} - \frac{8 X 1^1^6}{1^5}

\frac{d^2y}{dx^2} = 16 - 8\\\\\frac{d^2y}{dx^2}  = 8

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