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Blizzard [7]
3 years ago
7

If the acceleration of a moving object is zero, which of the following best describes its motion

Physics
2 answers:
podryga [215]3 years ago
7 0
If the acceleration of a moving object is zero, the object remains at a constant speed (without friction)
Morgarella [4.7K]3 years ago
3 0

Answer:

Explanation:

According to the newton's second law, the force exerted on an object is equal to the product of the mass of the body and the acceleration of the body.

F = m x a

Where, F is the force and a be the acceleration and m be the mass of the body.

Acceleration is defined as the rate of change of velocity of the body.

As acceleration is zero, so

a = 0

v - u = 0

Where, v is the final velocity of the body and u be the initial velocity of the body.

It means the body is moving with uniform velocity.

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Please help me there​
frozen [14]

Answer:

when switch is off no electricity will flow and then the circuit is called an open circuit

Explanation:

Electricity will not flow in open circuit

7 0
2 years ago
The most abundant state of matter in the universe is also the state with the most kinetic energy. That is
ella [17]

C)

Plasma is the most abundant state of matter in the universe and has the most kinetic energy. It can be found in all the planets of our solar system, the sun, and other stars

8 0
3 years ago
There is given an ideal capacitor with two plates at a distance of 3 mm. The capacitor is connected to a voltage source with 12
Licemer1 [7]

The kinematic energy of the positive charge is 2 10⁻⁸ J

This electrostatics exercise must be done in parts, the first part: let's start by finding the charge of the capacitor, the capacitance is defined by

        C = \frac{Q}{\Delta V}

        C = ε₀ \frac{A}{d}

we solve for the charge (Q)

        \frac{Q}{\Delta V} = \epsilon_o \frac{A}{d}

indicates that for the initial point d₁ = 3 mm = 0.003 m and the voltage is DV₁ = 12

         Q = \epsilon_o \  \frac{A \ \Delta V_1 }{d_1}

Now the voltage source is disconnected so the charge remains constant across the ideal capacitor.

For the second part, the condenser is separated at d₂ = 5mm = 0.005 m

         Q = \epsilon_o \  \frac{A \ \Delta V_2 }{d_2}

we match the expressions of the charge and look for the voltage

          \frac{\Delta V_1}{d_1} = \frac{\Delta V_2}{d_2}

          ΔV₂ = \frac{d_2}{d_1 } \ \Delta V_1

The third part we use the concepts of conservation of energy

starting point. With the test load (q = 1 nC = 1 10⁻⁹ C) next to the left plate

          Em₀ = U = q DV₂

          Em₀ = q  \frac{d_2}{d_1 } \ \Delta V_1

           

final point. Proof load on the right plate

         Em_f = K

energy is conserved

         Em₀ = em_f

         q  \frac{d_2}{d_1 } \ \Delta V_1 = K

   

we calculate

         K = 1 10⁻⁹  12  \frac{0.005}{0.003}  

         K = 20 10⁻⁹ J

In this exercise, as the conditions at two different points of separation give, the area of ​​the condenser is not necessary and with conservation of energy we find the final kinetic energy of 2 10⁻⁸ J

3 0
2 years ago
The force of kinetic friction between a box sliding on a surface depends on the ____ .
vazorg [7]

Answer: speed of the box

Explanation: maybe

6 0
2 years ago
Read 2 more answers
help me pass the test please there is a couple of questions in my profile to answer i am leaving this one for you to help ​
kompoz [17]

Answer:

0.5 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

a = (v – u) / t

a = (10 – 0) / 20

a = 10/20

a = 0.5 m/s²

Therefore, the acceleration of the car is 0.5 m/s².

6 0
2 years ago
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