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3 years ago

Does mgso4 dissolve via ionization

Chemistry

1 answer:

3241004551 [841]3 years ago

4 0

I dont think so......

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How many grams of AgNO3 are needed to make 250 ml of a solution that is 0.135 M

myrzilka [38]

Answer:

( About ) 5.7 grams

Explanation:

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4 years ago

I don’t know what are the ones that are left ,can someone help me please

disa [49]

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3 years ago

Arrange the following which is most reactive to the least reactive when these react in water:

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Answer:

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4 years ago

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Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data:A 80 mg sample of a crushed Vitam

Lina20 [59]

Answer:

The Answer is 88%

Explanation:

The balanced ionic equation of the reaction

$IO^{3- }+ 8 I^- + 6 H^+ => 3 I^{3- }+ 3 H_2O$

$I^{3-} + 2 S_2O_3^{2-} => 3 I^- + S_4O_6^{2-}$

$C_6H_8O_6 + I^{3- }+ H_2O => C_6H_6O_6 + 3 I^- + 2 H^+$

Looking at the above reactions

The original number of moles of $I^{3-}$ = 3 × number of moles of $IO^{3-}$

= 3 × volume × concentration of $KIO_3$

Note: The formula for number of moles is volume × concentration

$=3 * \frac{40}{1000} * 0.00653 =0.000784$ mol

The number of moles of $I^{3-}$ left after its reaction with ascorbic acid

= $\frac{1}{2}$ x moles of $S_2O_3^{2-}$

= $\frac{1}{2}$ x volume x concentration of $S_2O_3^{2-}$

$= \frac{1}{2} * \frac{15}{1000} * 0.0510 =0.000383 \ mol$

Note: The division by 1000 is to convert mill liter to liter

Moles of ascorbic acid = moles of $I^{3-}$ reacted

$= initial \ moles \ of \ I^{3-} \ - remaining \ moles \ of \ I^{3-}$

$=0.000784 - 0.000383$

$=0.000401 \ mols$

$Mass = moles \ * molar \ mass$

Hence

Mass of ascorbic acid = moles of ascorbic acid × molar mass of ascorbic acid

$= 0.000401* 176.12 = 0.07055\ g$

$= 70.55\ mg$

Weight% of ascorbic acid = mass of ascorbic acid/mass of sample x 100%

= 70.55/80 × 100%

= 88.1%

3 0

4 years ago

How many moles of the Htion in 395 mL of 1.325 M sulfuric acid (H2SO4).

Irina18 [472]

Answer:

1.05 mol

Explanation:

Step 1: Given data

Molarity of sulfuric acid (M): 1.325 M (1.325 mol/L)

Volume of solution (V): 395 mL (0.395 L)

Step 2: Calculate the moles of sulfuric acid (n)

We will use the following expression.

M = n/V

n = M × V

n = 1.325 mol/L × 0.395 L = 0.523 mol

Step 3: Calculate the moles of H⁺

H₂SO₄ dissociates completely according to the following equation.

H₂SO₄ ⇒ 2 H⁺ + SO₄²⁻

The molar ratio of H₂SO₄ to H⁺ is 1:2. The moles of H⁺ are 2/1 × 0.523 mol = 1.05 mol.

7 0

3 years ago