Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
Well, in math..
for example, There is triangle ABC, and ur translating it 3 units to the right on a grid...
The new triangle will be called A'B'C' cause its a new one... and to differenciate from the two, to not get mixed up, between them
Stepby-step explanation:
Hope I helped...
Brainliest, please??? Hee Hee
Answer:
Equation → 5y = 3y + 6
Value of ST = 15
Step-by-step explanation:
From the picture attached,
In right triangles ΔVST and ΔVUT,
Acute angles ∠SVT ≅ ∠UVT [Given]
TV ≅ TV [By reflexive property of congruence]
ΔVST ≅ ΔVUT [Hypotenuse angle congruence of right triangles]
Therefore, corresponding parts of the congruent triangles are congruent.
Therefore, ST ≅ TU
5y = 3y + 6
5y - 3y = 6
2y = 6
y = 3
Therefore, ST = 5y
ST = 5(3)
= 15