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Nostrana [21]
3 years ago
15

A train is approaching the station. Explain what happens to the frequency of the sound as the train draws closer. What do you he

ar? (4 points)
Physics
1 answer:
lisabon 2012 [21]3 years ago
8 0

If I am at the station that the train is approaching, and if the train is making some kind of steady sound, then as the train draws closer, I hear the amplitude of the sound steadily increasing ... it gets louder and louder as the train gets closer and closer to me.

(The frequency of the sound I hear is higher than the frequency of the sound the train is actually making, but I don't know that, because I have no idea what frequency sound the train is actually making.)

=================================

If anybody tries to tell you that the frequency of the sound from the train keeps getting higher and higher, please tell that person to come see me, and I will straighten him out.  It doesn't.

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Determine the initial velocity of the ball if it reaches a height of 15 meters.
jasenka [17]

Answer:

the initial velocity of the  ball is 17.14 m/s

Explanation:

Given;

maximum height reached by the ball, h = 15 m

let the initial velocity of the ball = u

at maximum height, the final velocity of the ball is zero, v = 0

The initial velocity of the ball is calculated by using the following upward motion kinematic equation;

v² = u² - 2gh

0 = u² - 2(9.8 x 15)

u² = 294

u = √294

u = 17.14 m/s

Therefore, the initial velocity of the  ball is 17.14 m/s

4 0
3 years ago
15 points. give me the method.
AveGali [126]

Answer:

\boxed{{160 \:  m(s)}^{ - 1} }

Explanation:

if \:the \:  frequencies \: are \to \\   f_{1} =  640Hz  \\ and \\f_{2}   = 480Hz \:  \\ but \:  \boxed{v = f \gamma }:   f =  \frac{v}{ \gamma } \\ if \:  \gamma_{1}  -  \gamma _{2}  = 1 =  \gamma  \\ f_{1}  - f_{2}  = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 =  \boxed{{160 \:  m(s)}^{ - 1} }

5 0
3 years ago
A 1400-kg car is moving at a speed of 35 m/s. How much kinetic energy does the car have (in Joules)?
Gekata [30.6K]

Answer:

857.5Kjoules

Explanation:

Using K. E=1/2 Mv^2

=1/2x1400x35x35

=857500joules

=857.5KJ

3 0
3 years ago
A toy cannon tosses a rubber ball straight upward. A motion sensor measures the speed of the ball as it leaves the cannon. Using
mezya [45]

Answer:

With this information is not possible to calculate the mass.

Explanation:

This is a characteristic problem of energy conservation, where kinetic energy becomes potential energy. For this particular problem, we have the initial speed as input data. The moment the ball comes out of the cannon we have the maximum kinetic energy, as the ball goes up the ball will gain more potential energy as the ball loses kinetic energy, until the moment the ball reaches the maximum height. At the maximum height point, the ball will have its maximum potential energy while its kinetic energy is zero. In other words, all the kinetic energy that was, in the beginning, was transformed into potential energy.

E_{p}=E_{k}\\m*g*h=0.5*m*v^2

In the above equation the masses are canceled and we can determine the maximum height, by means of the initial speed.

h=\frac{0.5*v^2}{g} [m]

But the mass cannot be determined, since it would be necessary to know the value of the energy, in order to determine the value of the mass.

3 0
3 years ago
All visible light (light that our eyes can detect) has a wavelength between 400-700 nanometers.  Wavelengths just smaller than 4
den301095 [7]

The Balmer light series comes under the visible light.

<u>Explanation:</u>

The transition of electrons from higher to energy level with 2 as principal quantum number results in the spectral emission lines of hydrogen atom and this series of lines are known as Balmer series.

Mostly, these lines has the wavelength of more than 400 nm but lesser than 700 nm. Generally of the four categories namely, 410, 434, 486, 656 nm which comes under the type of visible light. So, it can be concluded that the Balmer series light falls under visible light.

In astronomy, Balmer lines occur in various stellar (celestial or astronomical) objects due to the higher content of hydrogen in the universe. Therefore, they are commonly seen and relatively strong when compared to other element lines.

Note: nm is nanometer (one billionth of a meter in length)

4 0
3 years ago
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