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3 years ago

Which is described as the flow of charge particles?

Physics

1 answer:

Lady bird [3.3K]3 years ago

7 0

Electric current

For ex. The particles are in a strict

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g The magnetic force on a charged particle A. depends on the sign of the charge on the particle. B. depends on the velocity of t

Leona [35]

Answer:

E) is described by all of these

Explanation:

The magnetic force on a charged particle is expressed as:

F = qv * B = qvBsinθ

Where,

q = charge on particle

θ = angle between the magnetic field and the particle velocity.

v = velocity of the particle

B = magnitude of field vector

From here, we could denote that magnetic force, F depends on charge on particle, velocity of particle, magnitude of field vector.

The magnetic force on a charged particle is at right angles to both the velocity of the particle. The magnetic force and magnetic field in a charged particle are perpendicular to each other, the right hand rule is used to determine the direction of force.

The correct option is E.

3 0

3 years ago

Read 2 more answers

Why is weathering slow in cold, dry places?

Alexxandr [17]

Rate of weathering depends on temperature and moisture. Cold dry places have less water to weather things

Hope this helped!

Don't forget: Mark Brainliest!

Have a good day :)

6 0

3 years ago

A mass on a horizontal surface is connected to the spring and pulled to the right along the surface stretching the spring by 25

solniwko [45]

Answer:

320 N/m

Explanation:

From Hooke's law, we deduce that

F=kx where F is applied force, k is spring constant and x is extension or compression of spring

Making k the subject of formula then

$k=\frac {F}{x}$

Conversion

1m equals to 100cm

Xm equals 25 cm

25/100=0.25 m

Substituting 80 N for F and 0.25m for x then

$k=\frac {80}{0.25}=320N/m$

Therefore, the spring constant is equal to 320 N/m

3 0

4 years ago

A dart is thrown horizontally with an initial speed of 10 m/s toward point P, the bull's-eye on a dart board. It hits at point Q

Kryger [21]

D=s(t) so it would be d=10(.19) d=.19 FOR BITH SNDWERS

3 0

3 years ago

The record for the highest speed achieved in alaboratory for a

Ira Lisetskai [31]

Answer:

0.000234 seconds

Explanation:

Since the row is 0.15m, its radius of rotation must be 0.15 / 2 = 0.075 m

We can start by calculating the angular speed of the rod:

$\omega = \frac{v}{r} = \frac{2010}{0.075} = 26800 rad/s$

Since one revolution equals to 2π rad. The speed in revolution per second must be

26800 / 2π = 4265 revolution/s

The number of seconds per revolution, or period, is the inverse:

1/4265 = 0.000234 seconds

3 0

3 years ago