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sattari [20]
3 years ago
14

Which is described as the flow of charge particles?

Physics
1 answer:
Lady bird [3.3K]3 years ago
7 0
Electric current

For ex. The particles are in a strict
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Please answer this.
lilavasa [31]

Answer:

the answer is c

Explanation:

it's c because the moon has to be a full moon to be a solar eclipse when the sun moon and earth line up

6 0
3 years ago
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What are the 3 basic parts of an atom and what are their charges?
kotegsom [21]

Answer:

electrons neutrons and protons

Explanation:

electron are negative

nuetron are neutral

protons are positive

7 0
3 years ago
What is an accurate definition of a heat engine? A. a system that converts mechanical energy into thermal energy B. a system tha
Verizon [17]

Answer:

C

Explanation:

C. a system that converts thermal energy into other useful forms of energy

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3 years ago
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Suppose that the model presented by student 1 is correct. Based on the information provided, what would be the bond angle in a m
Ugo [173]

Question: Predicting the shape of a molecule is relatively straight forward. A molecule's shape will always be determined by the number of electron pairs around the central atom. The number of electron pair corresponds to the number of atoms that are bound to the central atom of the molecule. For example, water contains two hydrogen atom bound to one atom of oxygen, giving the molecule a linear geometry.

Suppose that the model presented by student 1 is correct. Based on the information provided, what would be the bond angle in a molecule of perchlorate ion.

Answer: Suppose that the model presented by student 1 is correct The (perchlorate ion) will be a tetrahedral shape, O-Cl-O bond angle 109.5 due to four groups of bonding electrons and no lone pairs of electrons.

8 0
3 years ago
A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th
Evgen [1.6K]

Answer:

\dfrac{d\theta}{dt}=0.038\ rad/s

Explanation:

Given that

\dfrac{dx}{dt}= -1\ m/s

From the diagram

tan\theta=\dfrac{21}{x}

By differentiating with time t

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

When x= 10 m

tan\theta=\dfrac{21}{10}

θ = 64.53°

Now by putting the value in equation

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

sec^264.53^{\circ} \dfrac{d\theta}{dt}=-\dfrac{21}{10^2}\times (-1)

\dfrac{d\theta}{dt}=0.038\ rad/s

Therefore rate of change in the angle is 0.038\ rad/s

8 0
3 years ago
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