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AysviL [449]
3 years ago
5

A rock falls off a cliff. How fast is the rock traveling vertically two seconds later?

Physics
1 answer:
Vikentia [17]3 years ago
8 0
The rock it traveling really, really fast.
It is hard to exactly determine how fast bc u need the height of the cliff and how big the rock is.
Hope this helps and can I get brainliest answer!
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A conservative force on a particle moving along the x axis is given by F = (3x^2-2x)i. Which of the following is a potential tha
ANTONII [103]

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5 0
2 years ago
Calculate the force, when a object acelerattes to 30 m/s^2 and have a mass of 40 kg
faust18 [17]

Hello!

Use the <u>second law of Newton:</u>

F = ma

Replacing:

F = 40 kg * 30 m/s^2

Resolving:

F = 1200 N

The force is <u>1200 Newtons.</u>

3 0
3 years ago
Read 2 more answers
Distance Between Two Cars A car leaves an intersection traveling west. Its position 4 sec later is 19 ft from the intersection.
faltersainse [42]

Answer:

The answer to the question is;

The rate at which the distance between the two cars is changing is equal to 14.4 ft/sec.

Explanation:

We note that the distance  traveled by each car after 4 seconds is

Car A = 19 ft in the west direction.

Car B = 26 ft in the north direction

The distance between the two cars is given by the length of the hypotenuse side of a right angled triangle with the north being the y coordinate and the  west being the x coordinate.

Therefore, let the distance between the two cars be s

we have

s² = x² + y²

= (19 ft)² + (26 ft)² = 1037 ft²

s = \sqrt{1037 ft^2} = 32.202 ft.

The rate of change of the distance from their location 4 seconds after they commenced their journeys is given by;

Since s² = x² + y² we have

\frac{ds^{2} }{dt} = \frac{dx^{2} }{dt}  + \frac{dy^{2} }{dt}

→ 2s\frac{ds }{dt} = 2x\frac{dx}{dt}  + 2y\frac{dy }{dt} which gives

s\frac{ds }{dt} = x\frac{dx}{dt}  + y\frac{dy }{dt}

We note that the speeds of the cars were given as

Car B moving north = 12 ft/sec, which is the y direction and

Car A moving west = 8 ft/sec which is the x direction.

Therefore

\frac{dy }{dt} =  12 ft/sec and

\frac{dx}{dt} = 8 ft/sec

s\frac{ds }{dt} = x\frac{dx}{dt}  + y\frac{dy }{dt} becomes

32.202 ft.\frac{ds }{dt} = 19 ft \times 8 \frac{ft}{sec}  + 26ft\times 12\frac{ft}{sec}  = 464 ft²/sec

\frac{ds }{dt} = \frac{464\frac{ft^{2} }{sec} }{32.202 ft.} = 14.409 ft/sec ≈ 14.4 ft/sec to one place of decimal.

3 0
3 years ago
Definition: The energy transferred by a force to a moving object.
Marysya12 [62]

Answer:

Force applied

Explanation:

An object will remain at its state of rest unless a non zero for act on it

6 0
3 years ago
As you walk away from a plane mirror on a wall yiur image is always a real image no matter how far you are from the mirror?
Alexus [3.1K]

Answer:

Correct option is D.

Explanation:

The size may change due to the distance from the mirror

I am 100% Sure about this answer

3 0
3 years ago
Read 2 more answers
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