An k incline plane has 2 = 40.0º and : = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m
/s?
2 answers:
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Answer:
6 m/s
Explanation:
Given that :
mass of the block m = 200.0 g = 200 × 10⁻³ kg
the horizontal spring constant k = 4500.0 N/m
position of the block (distance x) = 4.00 cm = 0.04 m
To determine the speed the block will be traveling when it leaves the spring; we applying the work done on the spring as it is stretched (or compressed) with the kinetic energy.
i.e
v = 6 m/s
Hence,the speed the block will be traveling when it leaves the spring is 6 m/s
Answer:
F_B = 6.4*10^-13 N
Explanation:
The magnetic force on the electron, generated by the motion of the electron and the magnetic field is given by:
q: electron charge = 1.6*10^{-19}C
v: speed of the electron = 2.0*10^6 m/s
B: magnitude of the magnetic field = 2T
However, the direction of B and v are perpendicular between them. So, the angle between vectors is 90°. The magnitude of the magnetic force is:
You replace the values of q, v and B in the last equation:
hence, the magnetic force on the electron is 6.4*10^-23 N