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evablogger [386]
3 years ago
14

An k incline plane has 2 = 40.0º and : = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m

/s?

Physics
2 answers:
ahrayia [7]3 years ago
4 0
Here's how I did it.  Let me know if you have a question

Alekssandra [29.7K]3 years ago
4 0

Answer: 2.31s

Explanation:

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What are the various types of technologies used for exploring space and understanding space
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1) Consider a situation where immediately after birth, twins are separated. One continues to live on earth, while the other is w
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No they will not look the same.
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4 years ago
Read 2 more answers
calculating power reach each scenario and then answer the questions scenario a 120 j of work is done in 6 seconds scenario b 160
Molodets [167]

Answer: scenario b and scenario c uses most power

Explanation:

Scenario a:

Work=120J

Time=8 seconds

Power=work ➗ time

Power=120 ➗ 8

Power=15

Power=15 watts

Scenario b:

Work=160J

Time=8 seconds

Power=work ➗ time

Power=160 ➗ 8

Power=20

Power =20 watts

Scenario c:

Work=200J

Time=10 seconds

Power= work ➗ time

Power=200 ➗ 10

Power=20

Power=20 watts

Scenario b and scenario c uses most power

4 0
4 years ago
A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the h
zloy xaker [14]

Answer:

Speed of lighter ball is 4 m/s.

Explanation:

Applying the principle of conservation of linear momentum,

momentum before collision = momentum after collision.

m_{1}u_{1} + m_{2} u_{2} = m_{1}v_{1} - m_{2}v_{2}

m_{1} = 3 kg, u_{1} = 8 m/s, m_{2} = 2 kg, u_{2} = 0 m/s ( since it is at rest), v_{1} = 2 m/s, v_{2} = ?

(3 x 8) + (2 x 0) = (8 x 2) - (2 x v_{2})

24 + 0 = 16 - 2v_{2}

2v_{2} = 16 - 24

2v_{2} = -8

v_{2} = \frac{-8}{2}

   = -4 m/s

This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.

7 0
3 years ago
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