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astraxan [27]
3 years ago
9

Find the sum of all positive integers less than 200, which:

Mathematics
1 answer:
Allushta [10]3 years ago
3 0

Answer:

3900

Step-by-step explanation:

We want the sum from 5 to 195

5, 10, 15, 20,......195

an = 5 + 5(n-1)  since we can write this as an arithmetic sequence, adding 5 each time

The sum of the terms of an arithmetic sequence is given by

Sn = n/2 [2a1 + (n - 1)d],  

where d is the common difference of 5 and n is the term we want to add to

195/5 = 39  so it is the 39th term

s39 =39/2 [2*5 + (39-1)*5)]

s38 = 19.5[10+38*5]

        =19.5*[10+190]

          19.5*200

          =3900


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Fantom [35]

Answer:

<h2>If we placed the number 10 in the box, we obtain a system of equations with infinitely many solutions.</h2>

Step-by-step explanation:

The given system is

y=2x-5\\2y-4x=a

<em>It's important to know that a system with infinitely many solutions, it's a system that has the same equation</em>, that is, both equation represent the same line, or as some textbooks say, one line is on the other one, so they have inifinitely common solutions.

Having said that, the first thing we should do here is reorder the system

y=2x-5\\2y=4x+a

This way, you can compare better both equations. If you look closer, observe that the second equation is double, that is, it can be obtained by multiplying a factor of 2 to the first one, that is

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So, by multiplying such factor, we obtaine the second equation. Observe that a must be equal to 10, that way the system would have infinitely solutions.

Therefore, the answer is 10.

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