A surfer is riding a wave with an amplitude of 6 feet and a period of 24 feet. If the wave completes a period in 8 seconds.The speed of the surfer is 3ft/sec.
A wave's amplitude is defined as its largest displacement on either side of its mean location.
The quantity of oscillations a wave makes in a second is referred to as frequency of wave.
The amount of time it takes to complete one vibration, from A to B, is referred to as time period.
As we know,
ν = λf
where, ν = speed
λ = wavelength
f = frequency
also,
Putting in the values in equation ν = λf gives us,
ν = 24 × ( period of wave must means wavelength of 24ft)
ν = 3ft/sec.
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Answer:
The present day model shows a nucleus composed of protons and neutrons with cloud-like spheres of different diameters surrounding the nucleus to represent the energy levels of the electrons in the atom. Rutherford's model shows electrons orbiting the nucleus along fixed, but similar- diameter circular paths.
Both models show the composition of the nucleus at the center of the atom and the much smaller electrons at some distance from the nucleus.
Explanation:
Neither of the models does a good job of representing the relative size differences of the protons, neutrons and electrons, or the distance between the nucleus and the "electron clouds."
The answer is:
when Bohr's original model stated that electrons were tiny little objects circling the nucleus along fixed orbits, however, this is no longer valid as we now know that rather "circling" the nucleus at confined orbits, electrons can seem to be everywhere at once
.
-So, The correct answer for this question would be QUANTIZATION OF ENERGY. The aspect of Bohr's original model of electron structure that is still included in the currently accepted theory of electron structure is the quantization of energy.
-Bohr suggested circular orbits of electrons around the nucleus of a hydrogen atom, but researches have shown that motion of the electron is not in a single plane., but it takes place in three-dimensional space. Actually, the atomic model is not flat
.
Answer:
The minimum thickness of the material is 114.5 nm
Explanation:
The remaining part of the question is as follows
What should the minimum thickness of the material be for it to be nonreflecting for light of wavelength 600 nm (in a vacuum)? Please give details of your reasoning.
Both reflections occur against a surface of higher index of refraction, so there is a phase shift at each reflection. The phase shifts cancel each other out, so if we want the emerging rays to be out of phase, we must have
Given
Index of refraction = 1.31
Index of refraction = 1.43
As we know
Here t is the thickness
represents the phase shift
n is the refraction index
Substituting the given values we get
nm
''Surface waves<span> are neither longitudinal nor </span>transverse<span>. In longitudinal and </span>transverse waves<span>, all the particles in the entire bulk of the medium move in a parallel and a perpendicular direction (respectively) relative to the direction of </span>energy<span> transport. ... Any </span>wave<span> moving through a medium has a source.''</span>