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jok3333 [9.3K]
3 years ago
8

you arrive at an intersection with traffic lights that arent working because of a power outage .what do you do

Physics
2 answers:
kobusy [5.1K]3 years ago
8 0

You would proceed as if the light is a stop sign.


ElenaW [278]3 years ago
6 0
Use it as a four way stop.
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you are sitting on a beach and a wave strikes the shore every 10 seconds. a surfer tells you that these waves travel at a speed
aev [14]

Answer:

50 meters

Explanation:

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3 years ago
Why is honesty especially important in a scientist when the results of an experiment go against predictions❓❔
kramer
Because other scientists and science in general rely on their collegues' research which in turn allows development of our knowledge on the given subject. The more dont-to-earth reason may be safety. If someone performs an experiment without knowledge of its true results it might result in some danger to the safety of those perforning it without knowledge of all the risks.
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3 years ago
19 dm expressed in millimeters
alina1380 [7]
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6 0
2 years ago
when 82.5 calories of heat are given to a metallic rod of mass 150g its temperature raises from 20 degree celcius to 25 degree C
marishachu [46]

A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.

<h3>What is specific heat?</h3>

It is the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

A metallic rod of mass 150 g (m) absorbs 82.5 cal of heat (Q) and its temperature raises from 20 °C to 25 °C. We can calculate the specific heat (c) of the metal using the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 82.5 cal / 150 g × (25 °C - 20 °C) = 0.11 cal/g.°C

A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.

Learn more about specific heat here: brainly.com/question/21406849

#SPJ1

8 0
2 years ago
A magnesium oxide component must not fail when a tensile stress of 10.5 MPa is applied. Determine the maximum allowable surface
Aloiza [94]

Answer:

Maximum permitted surface crack length is 1.29 mm

Explanation:

As per the question:

Tensile stress, \sigma = 10.5\ MPa = 10.5\times 10^{6}\ Pa

Surface energy of magnesium oxide, SE = 1.0\ J/m^{2}

Modulus of elasticity of the material, E = 225 GPa = 225\times 10^{9}\ Pa

Now,

To calculate the maximum allowable surface crack length:

L = \frac{2E\times SE}{\sigma^{2}\pi }

L = \frac{2\times 225\times 10^{9}\times 1.0}{10.5\times 10^{6}\times \pi } = 1.29\times 10^{- 3}\ m = 1.29\ mm

7 0
4 years ago
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