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RUDIKE [14]
3 years ago
5

A light beam is incident on a piece of fluorite (n = 1.434) at the Brewster's angle.

Physics
1 answer:
trasher [3.6K]3 years ago
5 0
The Brewster angle is the angle can be found through this equation
θ=arctan(n2/n1).
This came from Snell's Law:
n1sinθ=n2sin(90-θ)
          =n2cosθ
n2/n1=tanθ --- θ=arctan(n2/n1)=arctan(1.434)=55.11 degrees

Next, the angle of refraction can be found by using Snell's Law
n1sinθ=n2sinθ'
sin(55.11)=1.434sinθ'
sinθ'=sin(55.11)/1.434=0.572 --- θ'=arcsin(0.572)=34.89 degrees
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A boy jumps from a wall 3m high. What is an estimate of the change in momentum of the boy when he lands without rebounding?
EastWind [94]
The answer is D. Because the boy jump 3 high
8 0
3 years ago
A ball is thrown straight up with a velocity of 50 m/s.(use g = -10 m/s^2) a) What is the velocity in m/s after 2 seconds?
Andrei [34K]

Answer:

(a) 30 m/sec

(b) -50 m/sec

Explanation:

We have given initial velocity of ball u = 50 m/sec

Acceleration due to gravity g=-10m/sec^2

(a) Time t = 2 sec

Now according to first equation of v = u-gt

So v=50-10×2=30 m/sec

(b) Time t = 10 sec

Now according to first equation of motion

So final velocity v = u-gt = 50-10×10 =-50 m/sec

3 0
3 years ago
2. 3000. kg car is moving across level ground at 5.0 m/s when it begins an
gizmo_the_mogwai [7]

Answer:

yes

Explanation: Work is done when there is movement. Therefore it was work was being done.

7 0
2 years ago
Will give brainliest!
tamaranim1 [39]
Howdy!!

your answer is ----


total resistance 1/R = 1/9+1/9+1/9
= 3/9

=> R = 9/3 = 3 ohm
according to ohms law

voltage = current × resistance

= 4 × 3 = 12 volt


hope it help you
8 0
3 years ago
A proton is projected perpendicularly into a magnetic field that has a magnitude of 0.50 T. The field is then adjusted so that a
bixtya [17]

Answer:

B_e = 2.72 \times 10^{-4} T

Explanation:

As we know that when charge particle is projected in perpendicular magnetic field then the radius of the charge particle is given as

F = qvB

\frac{mv^2}{r} = qvB

now we have

r = \frac{mv}{qB}

since here radius of proton and electron will be same

so we will have

r_e = r_p

\frac{m_e v}{q_e B_e} = \frac{m_p v}{q_p B_p}

so we have

B_e = \frac{B_p m_e}{m_p}

given that

B_p = 0.50 T

m_e = 9.11 \times 10^{-31} kg

m_p = 1.67 \times 10^{-27} kg

so we have

B_e = \frac{0.50(9.11\times 10^{-31})}{1.67\times 10^{-27}}

B_e = 2.72 \times 10^{-4} T

4 0
2 years ago
Read 2 more answers
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