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RUDIKE [14]
3 years ago
5

A light beam is incident on a piece of fluorite (n = 1.434) at the Brewster's angle.

Physics
1 answer:
trasher [3.6K]3 years ago
5 0
The Brewster angle is the angle can be found through this equation
θ=arctan(n2/n1).
This came from Snell's Law:
n1sinθ=n2sin(90-θ)
          =n2cosθ
n2/n1=tanθ --- θ=arctan(n2/n1)=arctan(1.434)=55.11 degrees

Next, the angle of refraction can be found by using Snell's Law
n1sinθ=n2sinθ'
sin(55.11)=1.434sinθ'
sinθ'=sin(55.11)/1.434=0.572 --- θ'=arcsin(0.572)=34.89 degrees
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The length of a simple pendulum is 0.66 m, the pendulum bob has a mass of 310 grams, and it is released at an angle of 12 degree
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c) total energy = KE + GPE = KE when GPE is equal to zero (at the lowest point possible)
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