Answer:
86.51° North of West or 273.49°
Explanation:
Let V' = velocity of boat relative to the earth, v = velocity of boat relative to water and V = velocity of water.
Now, by vector addition V' = V + v'.
Since v' = 6.10 m/s in the north direction, v' = (6.10 m/s)j and V = 100 m/s in the east direction, V = (100 m/s)i. So that
V' = V + v'
V' = (100 m/s)i + (6.10 m/s)j
So, we find the direction,Ф the boat must steer to from the components of V'.
So tanФ = 6.10 m/s ÷ 100 m/s
tanФ = 0.061
Ф = tan⁻¹(0.061) = 3.49°
So, the angle from the north is thus 90° - 3.49° = 86.51° North of West or 270° + 3.49° = 273.49°
Thus, more than 30 J of potential energy can be loosed by the ball. Thus, the gravitational potential energy of the ball is more than 30 J.
If there is no air resistance, the ball's potential energy is entirely transformed into kinetic energy. When air resistance is taken into account, a portion of the potential energy is used to overcome it. Thus, AU > AKE. In the current scenario, a ball gains 30 J of kinetic energy while falling and is treated as encountering air resistance. The energy that an object retains due to its position in relation to other objects, internal stresses, electric charge, or other factors is known as potential energy in physics. The potential energy will be transformed into kinetic energy if the stones fall. High on the tree, branches have the potential to fall, which gives them energy. Chemical potential energy exists in the food we eat.
Learn more about potential energy here:
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I dont know if insurance can help u sweeid
Answer:
I = 0.451 amp
Explanation:
given,
C = 8.0 µF
V = 2 V
resistor connected between two terminal = 6 Ω
current flowing through resistor = 13 µsec
Q = CV
Q = 8 x 2
Q = 16 µC
for an RC discharge circuit
V = V_0e^{-\dfrac{t}{RC}}
I = \dfrac{-Q_0}{RC}e^{-\dfrac{t}{RC}}
t = 13 µsec
I = \dfrac{-16}{6\times 2}e^{-\dfrac{13}{6\times 2}}
I = 0.451 amp
neglecting -ve sign just to show direction.
Your taste buds that are located on your tongue
