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Alisiya [41]
3 years ago
9

If you are driving 72 km/h along a straight road and you look to the side for 4.0 s, how far do you travel during this inattenti

ve period? .
Physics
1 answer:
Ann [662]3 years ago
8 0
We know that speed equals distance between time. Therefore to find the distance we have that d = V * t. Substituting the values d = (72 Km / h) * (1h / 3600s) * (4.0 s) = 0.08Km.Therefore during this inattentive period traveled a distance of 0.08Km
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What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??
Fittoniya [83]

Answer:

F = 37.5 N

Explanation:

It is given that,

Mass of the object is 5 kg

Acceleration of the object is 7.5 m/s²

We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,

F = m

F=5\times 7.5\\\\F=37.5\ N

So, the force acting on the object is 37.5 N.    

4 0
4 years ago
Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Gelneren [198K]

The average speed between 0 h and 2.340 h is 6.97 Km/h

Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

Average \: speed =  \frac{total \: distance}{total \: time}  \\  \\

With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:

  • Total time = 2.340 – 0 = 2.340 h
  • Total distance = 16.3 – 0 = 16.3 Km
  • Average speed =?

Average \: speed =  \frac{total \: distance}{total \: time}  \\  \\Average \: speed =  \frac{16.3}{2.340}  \\  \\ Average \: speed = 6.97 \: Km/h \\  \\

Learn more about average speed: brainly.com/question/24884027

8 0
2 years ago
a horizontal clothesline is tied between 2 poles, 10 meters apart. when a mass of 1 kilograms is tied to the middle of the cloth
natali 33 [55]

By analyzing the vector, the clothesline tension is 25 N.

We need to know about vectors to solve this problem. Force is included in vectors that have magnitude and direction. It can be written as

F = (Fx i + Fy j) N

where F is the force vector, Fx is the x-axis component and Fy is the y-axis component.

From the question we know that :

x = 10 m

(midpoint = 5m)

y = 1 m

m = 1 kg

Find the weight

W = m . g

W = 1 x 10

W = 10N

There are two y-axis components of the tension that hold the clothes. Because of static conditions, we can write

∑Fy = 0

Ty + Ty - W = 0

2Ty - 10 = 0

2Tsinθ - 10 = 0

Find sinθ

sinθ = y/x

sinθ = 1/5

Substitute the sinθ

2Tsinθ - 10 = 0

2T(1/5) - 10 = 0

2T/5 = 10

T = 25 N

Hence, the clothesline tension is 25 N.

For more about vectors at: brainly.com/question/25811261

#SPJ4

6 0
1 year ago
We use __force to do different force. 1) pulling 2)pushing 3)gravity 4)muscular
soldier1979 [14.2K]

Answer:

gravity

Explanation:

We use gravity to do different force.

3 0
3 years ago
When stopping at a stop sign where there is no crosswalk or stop line, a driver should stop his/her vehicle: A Before the back o
Thepotemich [5.8K]

Answer:

Before the front of the vehicle enters the intersection.

Explanation:

When stopping at a stop sign where there is no crosswalk or stop line, a driver should stop his/her vehicle before the front of the vehicle enters the intersection.

The front part of the vehicle comes in contact initially. On the other hand, the back part comes after that.

Hence, the correct option is (b).

3 0
3 years ago
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