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Alisiya [41]
3 years ago
9

If you are driving 72 km/h along a straight road and you look to the side for 4.0 s, how far do you travel during this inattenti

ve period? .
Physics
1 answer:
Ann [662]3 years ago
8 0
We know that speed equals distance between time. Therefore to find the distance we have that d = V * t. Substituting the values d = (72 Km / h) * (1h / 3600s) * (4.0 s) = 0.08Km.Therefore during this inattentive period traveled a distance of 0.08Km
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a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i
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Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
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where a is acceleration,
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Vi is initial velocity, and
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Substituting,
            a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>

Part B: 
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
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Substituting,
              F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

<em>ANSWER: 240 N </em>

Part C: 
The distance that the sprinter travel is calculated through the equation,
         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
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<em>ANSWER: d = 13.5 m</em>

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KengaRu [80]

Answer:

2.48 m/s

Explanation:

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