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3 years ago

The total potential and kinetic energy of the particles in an object is called

2 answers:

3 0

It can also be called the thermal kinetic energy. The internal energy of a system is the total thermal kinetic energy and thermal potential energy of all its atoms and molecules. The Kinetic Theory of Matter is explains the kinetic energy of particles in an object.

Setler79 [48]3 years ago

3 0

I think it's thermal energy..

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If a current of 0.5 A flows in a 75 W light bulb when the voltage difference between the ends of the filament is 150 V, what is

serious [3.7K]

Power is current times voltage. Using Ohm's Law V=IR, we can express power in two additional ways:
$P=I^2R \\ P= \frac{V^2}{R}$
So for P=75W, we can use either of these to get R. Let's use the first one:
$75W=(0.5A)^2R \\ \frac{75W}{0.25A^2}=300 \Omega$

3 0

3 years ago

For a relative frequency distribution, relative frequency is computed is computed as ____________.

Yuliya22 [10]

Answer:

For a relative frequency distribution, relative frequency is computed as the class frequency divided by the number of observations.

6 0

2 years ago

Assume that block A is accelerating with block B at a rate of 0.800 m/s2 along a frictionless surface. What is the mass of both

zlopas [31]

Answer:

The mass of A and B together is 125kg

Explanation:

To solve this problem, we set up the equations expressing the net force acting on A and B (forces acting to the right are +, those acting to the left are -):

$m_B\cdot a_B=F - F_{fr}\\m_A\cdot a_A = F_{fr}\\a_A = a_B$

The net force acting on B is due to the acting pull force 100N less friction force caused by A. The net force on A is due to the friction force caused by the block B. Since we know both blocks accelerate at the same rate, the system can be solved easily:

$(m_B+m_A)\cdot a_B=F\\(m_B+m_A)\cdot 0.800 \frac{m}{s^2}=100N\implies\\m_B+m_A = \frac{100N}{0.800\frac{m}{s^2}}kg= 125kg$

Of course, alternatively, in this very simple case you could consider A+B a single object being pulled with 100N, and obtain the same results by diving the pull force by the acceleration.

6 0

4 years ago

A small lead ball, attached to a 1.5-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled a

jarptica [38.1K]

Answer:

H=10.93 m

Explanation:

Given that

h'= 0.75 m

r= 1.5 m

ω = 3 rev/s

ω = 3 ₓ 2 π rad/s

ω = 6 π rad/s

Speed of the ball when it releases from the rope,V.

V= ω x r

V= 6 π x 0.75

V=14.13 m/s

We know that acceleration due to gravity always in downward direction.

$V_f^2=V_o^2+2as$

The final speed will be zero

$0=14.123^2-2\times 9.81 \times h$

h = 10.18 m

So the height from the ground,H = h' + h

H= 10.18 + 0.75 m =10.93 m

H=10.93 m

8 0

3 years ago

A ball is thrown vertically downward with an initial speed of 12.0 m/s from a height of 10.0 m above the ground. Ignoring air re

natita [175]

Answer:

18.5 m/s

Explanation:

Take down to be positive.

Given:

Δy = 10.0 m

v₀ = 12.0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (12.0 m/s)² + 2 (10 m/s²) (10.0 m)

v = 18.5 m/s

8 0

3 years ago