Answer:
The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m
Explanation:
Given that,
First charge = 40 μC
Second charge = 80 μC
Distance between the two particles = 2.0 m
Kinetic energy = 16 J
We need to calculate the distance separating the two particles when the moving particle is momentarily stopped
Using conservation of energy
Put the value into the formula
Hence, The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m
Carbon Monoxide is a mixture because its a simple compound with 2 elements, carbon and oxygen are bonded together
(NH4)2CO3(s) ⇄ 2NH3(g) + CO2(g) + H2O (g)
The effect that adding water (H2O) have in reaction above is that The concentration of the product would decrease, and the concentration of reactant would increase. (answer C)
<u><em>Explanation</em></u>
- If the concentration of one substance is changed, the equilibrium shift to minimize the effect of that change.
- H2O in reaction above is a product.
- Increase of water (H2O) concentration will led to the shift of equilibrium to the left ( reactant side) .The concentration of reactant increase as that of product decrease.
