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Hitman42 [59]
2 years ago
8

Which description best characterizes the motion of particles in a solid?

Chemistry
2 answers:
antoniya [11.8K]2 years ago
5 0

The particles in a solid are tightly packed and locked in place. Although we cannot see it or feel it, the particles are vibrating in place.

As these molecules heat up, they will vibrate more vigorously, and will eventually turn to water, then gas.

kirza4 [7]2 years ago
4 0

Answer:

Hardly move and vibrate

Explanation:

in solids particles are packed thight together

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What salt is produced in each of the following neutralization reactions?
Pavlova-9 [17]

1. Salt is KNO₃<span>

<span>This is a </span>strong acid - strong base<span> <span>reaction. </span></span>HNO</span>₃ is the strong acid<span> <span>and </span></span>KOH is the strong base<span>. </span><span>

H</span>⁺<span> in the HNO₃<span> and </span></span>OH⁻<span> <span>of the KOH pair up and make </span></span>H₂O(l)<span>. </span><span>

NO</span>₃⁻<span> <span>and </span></span>K⁺<span> <span>pair up to make </span></span>KNO₃ salt<span>. </span><span>

<span>When writing chemical formulas </span>positive ion comes first<span> <span>and second is negative ion. The charges should be switched. Since </span></span>positive ion has +1 and negative ion has -1<span> <span>after the switching off charges </span>the </span>product should be KNO</span>₃.<span>

Balance equation is </span><span>
HNO</span>₃<span>(aq) + KOH(aq) → H</span>₂O(l) + KNO<span>₃(aq)</span><span>
<span>
2. Salt is Ca(NO</span></span>₃)₂<span>

</span>This is a strong acid - strong base<span> reaction. </span>HNO₃ is the strong acid<span> and </span>Ca(OH)₂ is the strong base<span>. </span><span>
<span>
H</span></span>⁺<span> in the HNO₃ and </span>OH⁻<span> of the Ca(OH)₂ pair up and make </span>H₂O(l)<span>. </span><span>

Ca²⁺ and </span>NO₃⁻<span>  pair up to make </span>Ca(NO₃)₂ salt<span>. </span><span>
<span>
</span><span>Positive ion is </span>Ca²⁺<span> which has </span></span>+2 charge<span> and negative ion is</span> NO₃⁻<span> <span>which has </span></span>-1 charge<span>. From switching the charges </span>Ca²⁺ gets 1<span> <span>while </span></span>NO₃⁻ gets 2.<span> Hence, the salt should be </span>Ca(NO₃)₂.<span>

Balanced equation is 
</span>2HNO₃<span>(aq) + Ca(OH)</span>₂<span>(aq) → 2H</span>₂O(l) + Ca(NO<span>₃)₂(aq)</span><span>
<span>
3. Salt is CaCl</span></span>₂<span>

This is a strong acid - strong base<span> reaction. </span>HCl is the strong acid<span> and </span>Ca(OH)</span>₂ is the strong base<span>. </span><span>
<span>
H</span></span>⁺<span> in the HCl and </span>OH⁻<span> of the Ca(OH)₂ pair up and make </span>H₂O(l)<span>. </span><span>

Ca²⁺ and </span>Cl⁻<span> pair up to make </span>CaCl₂ salt<span>. </span><span>
<span>
</span><span>Positive ion is </span>Ca²⁺ which has </span>+2 charge<span> and negative ion is</span> Cl⁻<span> which has </span>-1 charge<span>. By switching the charges </span>Ca²⁺ gets 1<span> while </span>NO₃⁻ gets 2.<span> Hence, the salt should be </span>CaCl₂.<span>

Balance equation is 
</span><span>2HCl(aq) + Ca(OH)</span>₂<span>(aq) → 2H</span>₂O(l) + CaCl₂<span>(aq)

4. Salt is KCl<span>

</span>This is a strong acid - strong base<span> reaction. </span>HCl is the strong acid<span> and </span>KOH is the strong base<span>. </span>
<span>
H</span></span>⁺<span> in the HCl and </span>OH⁻<span> of the KOH pair up and make </span>H₂O(l)<span>. </span><span>

K</span><span>⁺ and </span>Cl⁻<span> pair up to make </span>KCl salt<span>. </span><span>
<span>
</span><span>Positive ion is K</span></span><span>⁺ which has </span>+1 charge<span> and negative ion is</span> Cl⁻<span> which has </span>-1 charge<span>. By switching the charges </span>K⁺ gets 1<span> and </span>Cl⁻ also gets 1.<span> Hence, the salt should be </span>KCl.<span>

Balance equation is 
</span><span>HCl(aq) + KOH(aq) → H</span>₂<span>O(l) + KCl(aq)</span>

5 0
3 years ago
Read 2 more answers
Let's just say I want to get my mixture to a certain pH but I add too much water to my solution. Can I just add the same volume
Dafna11 [192]

Answer:

You can

Explanation:

The concentration doesn't change when its equals out.

4 0
3 years ago
A piece of sodium metal can be described as?
vlada-n [284]

Answer:

A piece of sodium metal can be described as a pure substance and an element. ... Sodium is a soft, waxy, silvery, highly reactive metal. Sodium belongs to group 1 of the periodic table and it is highly abundant in the earth's crust. Sodium can also be found in various minerals such as rock salt, feldspars and sodalite.

Explanation:

here is short description that will help u 2 understand more

Thx

6 0
3 years ago
Read 2 more answers
You decide to clean the bathroom. You notice that the shower is covered in a strange green slime . you try to get rid of this sl
Free_Kalibri [48]
  1. The independent variable (IV) is the lemon juice mixture
  2. The dependent variable (DV) is the appearance of the green slime on the shower
  3. The control variable (CV) are time taken to spray, the amount of spray
  4. The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
  5. The control group (CG) is the side of the shower sprayed with water.

INDEPENDENT VARIABLE

  • Independent variable is the variable of an experiment that is changed by the experimenter in order to bring about a change. It is the variable being tested in the experiment. In this case, the IV is the lemon juice mixture tested on the green slime on the shower.

DEPENDENT VARIABLE:

  • Dependent variable is the variable that is observed or measured in an experiment. It is also called responding variable. The DV in this case is the appearance of the green slime on the shower.

CONTROL VARIABLE:

  • Control variable is the variable that is kept constant throughout the experiment for all groups. The CV is the same for all the groups and they include: time taken to spray, the same amount of spray

CONTROL GROUP

  • Control group is the group that does not receive the independent variable or test in an experiment. In this case, the CG is the side of the shower sprayed with water.

EXPERIMENTAL GROUP:

  • Experimental group is the group of ab experiment that receives the experimental treatment or independent variable. In this case, the EG is the side of the shower sprayed with lemon juice mixture.

Therefore, the IV, DV, CV, EG and CG of this experiment are as follows:

  1. The independent variable (IV) is the lemon juice mixture
  2. The dependent variable (DV) is the appearance of the green slime on the shower
  3. The control variable (CV) are time taken to spray, the amount of spray
  4. The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
  5. The control group (CG) is the side of the shower sprayed with water.

Learn more: brainly.com/question/17498238?referrer=searchResults

7 0
2 years ago
Determine the oxidation state of each of the following species.<br> Pb2+
mafiozo [28]

Answer:

Pb oxidation number is +2

C in CH4 is -4. H is +1. 4H + 1C = 0. ; 4(+1) + C = 0 ; C = -4

O is usually -2. 3O = 3(-2) = -6. ; 2Fe =. +6 ; each Fe is +3

2Ag = +2 since O = -2 ; each Ag = +1

6 0
3 years ago
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