How do you solve 2 (5-6) < 8f - 130
1 answer:
2(5-6)<8f-130
(2x5)-(2x6)<8f-130
10-12<8f-130
-2<8f-130
-2+130<8f-130+130
128<8f
128/8<8f/8
16<f
f>16
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Answer:
Midpoint is ( Average of x’s, Average of y’s )
1 = (x + 7)/2
2 = x + 7, x = - 5
and - 1 = (y + (-4))/2
so - 2 = y - 4 and y = 2
Pt B = (- 5, 2)
Answer:
first one yes
Step-by-step explanation:
second one its
39x+10=180
Wait sorry in fraction for it is 1000000/10
Answer:
v = 0
Step-by-step explanation:
12 = 12 + v / 8
0 = 1/8v
v = 0
Creo que es A si no es porfavor dime.
