Answer:
Magnitude of the acceleration due to gravity on the planet = 2.34 m/s²
Explanation:
Time period of simple pendulum is given by
, l is the length of pendulum, g is acceleration due to gravity value.
We can solve acceleration due to gravity as
Here
Length of pendulum = 1.20 m
Pendulum executes simple harmonic motion and makes 100 complete oscillations in 450 s.
Period,
Substituting
Magnitude of the acceleration due to gravity on the planet = 2.34 m/s²
Answer:
θ = 56.09°
Explanation:
Given that
h = 8.5 ft
speed ,u= 28 ft/s
We know that acceleration due to gravity g
g= 32.2 ft/s²
The maximum height h is given as
Now by putting the values
θ = 56.09°
Therefore the angle will be θ = 56.09°
Assuming negligible air resistance, the shell travels at a constant horizontal velocity equal to what it had immediately after leaving the barrel. The shell is in the air until hitting the target; the length of this period of time is therefore directly proportional to the distance between the barrel and the target.
The shell hits the target below where it was aimed at for it experiences gravitational pull during its flight. With the barrel pointed "parallel to the ground" the shell shall experience no initial vertical velocity, meaning that it its undergoing a freefall on the vertical direction. and are therefore the respective vertical displacements of the two trials.
The formula below relates the vertical displacement to the gravitational acceleration and the time duration of the freefall :
Let and be the duration of the shell's flight on the first and second trials, respectively; Thus