Do you mind if I use this example for my assignment?

What net force is necessary to keep a 1.0 kg puck moving in a circle of radius 0.5 m on a horizontal frictionless surface with a

Diano4ka-milaya [45]

Answer:

8.0 N

Explanation:

8 0

3 years ago

A water trough is m long and a cross-section has the shape of an isosceles trapezoid that is cm wide at the bottom, cm wide at t

Aleonysh [2.5K]

The rate of water level rising when the water is 30 cm deep will be 1/30 m/min.

<h3 /><h3>What is volume?</h3>

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

The complete question is;

"A water trough is 10m long and has a cross-section which is the shape of an isosceles trapezoid

that is 30cm wide at the bottom, 80cm wide at the top, and has a height of 50cm. If the trough is being filled with water at the rate of 0.2 m3/min, how fast is the water level rising when the water is 30cm deep?"

b1 is the width of the water at a height at the bottom

b2 is the width of the water at the height at the top

The length of the trapezoid is L

The volume of the trapezoid is found as;

$\rm V = 0.5(b_1 + b_2)hL$

The breadth rises by 1 as the height does, therefore which implies

$\rm \frac{dh}{dt} =\frac{dw}{dt}$

The water's breadth at the combined height is [0.3 + h]

$\rm V = 5h(0.3 +(0.3 + h))\\\\ V = 3h + 5h^2$

After differentiation we get;

$\rm \frac{dv }{dt} =3 \frac{dh}{dt} +10 h \frac{dh}{dt} \\\\\ \frac{ \frac{dv }{dt}}{3+10h}=\frac{dh}{dt} \\\\\ \frac{dv }{dt}= 0.2 \\\\\ h = 0.3 \\\\ \frac{dh}{dt} = \frac{1}{30} m/min$

Hence the rate of water level rising when the water is 30 cm deep will be 1/30 m/min.

To learn more about the volume, refer to brainly.com/question/1578538.

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6 0

2 years ago

One method of getting a tight fit, say of a metal peg in a hole in a metal block, is to manufacture the peg slightly larger than

Novay_Z [31]

The block should be colder than the peg during insertion.

To find the answer, we have to know more about the thermal expansion of metal.

<h3>What is thermal expansion of metal?</h3>

Metals' Thermal Expansion The phenomenon of material expanding on heating and contracting on cooling is now well-known.
An object changes in size when heated. Depending on the body's form. It is known as linear expansion if the expansion takes place linearly.

The peg should be warmer than the metal block.
Since the metal peg is made larger, the temperature of the metal block should be lower than that of the peg in order for the metal block's thermal expansion to provide a tight fit when the peg is inserted into the hole and the temperature rises.

Due to the metal's tendency to expand as temperature rises, the hole's size decreases.
As a result, at the time of insertion, the metal block's temperature should be lower than the peg's temperature.

Thus, we can conclude that, the block should be colder than the peg during insertion.

Learn more about thermal expansion here:

brainly.com/question/28103765

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7 0

2 years ago

Which of the following is one way creativity can help scientists? (20 points) +Brainiest

Pavlova-9 [17]

Your answer would be B love!

8 0

3 years ago

You place a mass of 250 grams on the measurement tray of a triple beam balance and then set the rider on the 500 gram beam to th

WARRIOR [948]

"<span>The pointer will be above the zero mark" is the one statement among the following choices given in the question that is true. The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your great help.</span>

3 0

4 years ago

Read 2 more answers