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finlep [7]
4 years ago
9

Astronauts on a distant planet set up a simple pendulum of length 1.20 m. The pendulum executes simple harmonic motion and makes

100 complete oscillations in 450 s. What is the magnitude of the acceleration due to gravity on this planet?
Physics
1 answer:
Ray Of Light [21]4 years ago
4 0

Answer:

Magnitude of the acceleration due to gravity on the planet = 2.34 m/s²

Explanation:

Time period of simple pendulum is given by

         T=2\pi\sqrt{\frac{l}{g}}, l is the length of pendulum, g is acceleration due to gravity value.

We can solve acceleration due to gravity as

            g=\frac{4\pi^2l}{T^2}

Here

  Length of pendulum = 1.20 m

  Pendulum executes simple harmonic motion and makes 100 complete oscillations in 450 s.

  Period, T=\frac{450}{100}=4.5s

Substituting

         g=\frac{4\pi^2\times 1.2}{4.5^2}=2.34m/s^2

Magnitude of the acceleration due to gravity on the planet = 2.34 m/s²

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3 years ago
On a spring scale that measures force, a reading shows the force of an object to be about halfway between 7 N and 8 N. Which of
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6. Two blocks are released from rest at the same height. Block A slides down a steeper ramp than Block B. Both ramps are frictio
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Answer:

a. the work done by the gravitational force on Block A is <u>less than</u> the work done by the gravitational force on Block B.

b. the speed of Block A is <u>equal to</u> the speed of Block B.

c. the momentum of Block A is <u>less than</u> the momentum of Block B.

Explanation:

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w = m*g*h

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v = √(2*g*h)

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8 0
3 years ago
A person uses eyeglasses with a power of -5.5 D. The lenses are 1.8 cm from the person's eye. What is the furthest this person c
bija089 [108]

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But closest answer from the given options is option B.Hence, 20 cm is the correct answer.

6 0
3 years ago
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