You just have to isolate x, so just divide by WQ on both sides to get:
Answer:
Elemental S reacts with O2 to form SO3 according to the reaction 2S+3O2→2SO3 Part B: What is the theoretical yield of SO3 produced by the quantities described in Part A? Express your answer numerically in grams.
Part A: 1.88x10^23 O2 molecules are needed to react with 6.67 g of S.
We address the equation...
S
(
s
)
+
3
2
O
2
(
g
)
→
S
O
3
(
g
)
Explanation:
The question specifies that we got
1.88
×
10
23
dioxygen molecules
...i.e. a molar quantity of...
1.88
×
10
23
⋅
molecules
6.022
×
10
23
⋅
molecules
⋅
m
o
l
−
1
=
0.312
⋅
m
o
l
...
But we gots with respect to sulfur,
6.67
⋅
g
32.06
⋅
g
⋅
m
o
l
−
1
=
0.208
⋅
m
o
l
...
And a bit of arithmetic later, we establish that we got stoichiometric quantities of dioxygen, and sulfur….in the reaction we produce a mass of ………..
0.208
⋅
m
o
l
×
80.07
⋅
g
⋅
m
o
l
−
1
=
16.65
⋅
g
.
Note that when
sulfur trioxide
is made industrially (and this a very important commodity chemical), sulfur is oxidized to
S
O
2
, and this is then oxidized up to
S
O
3
with some catalysis...
S
O
2
(
g
)
+
1
2
O
2
(
g
)
V
2
O
5
−−→
S
O
3
(
g
)
S
O
3
(
g
)
+
H
2
O
(
l
)
→
H
2
S
O
4
(
a
q
)
sulfuric acid
The industrial sulfur cycle must be a dirty, smelly, unfriendly process. The process is undoubtedly necessary to support our civilization....
DNA replication is the process by which DNA makes a copy of itself during cell division. The first step in DNA replication is to 'unzip' the double helix structure of the DNA? molecule. ... The separation of the two single strands of DNA creates a 'Y' shape called a replication 'fork'.
Answer: I think its that cellular respiration results in water, carbon dioxide, and ATP but photosynthesis results in oxygen and glucose so they are opposites
Explanation: HAVE A GREAT DAY :)
Answer:
1.85 g
Explanation:
The strategy here is to utilize the Henderson-Hasselbach equation
pH = pKa + log [A⁻] / [HA]
to calculate the ratio log [A⁻] / [HA], and from there to calculate the concentration [A⁻] and finally the mass of NaNO₂ from the number of moles assuming the final buffer volume is 50.0 mL ( that is the volume does not change by the addition of NaNO₂)
pH = pKa + log [NO₂⁻]/[HNO₂]
3.13 = 3.40 + log [NO₂⁻]/[HNO₂]
- 0.27 = log [NO₂⁻]/[HNO₂]
taking the inverse log function to both sides of this equation
0.54 = [NO₂⁻]/[HNO₂]
Now [HNO₂] = 1.0 M, therefore [NO₂⁻] = [NaNO₂] =
0.54 x 1.0 M = 0.54 M
from M = mol / L we get
mol = 0.54 mol/L x 0.050L = 0.027 mol
the molar mass of NaNO₂ is = 68.99 g / mol, so the mass of 0.027 mol is
0.027 mol x 68.99 g/mol = 1.85 g