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ElenaW [278]
3 years ago
7

What is the energy of a photon of red light that has a frequency of 4.48 X 10^14Hz?

Chemistry
1 answer:
lana [24]3 years ago
3 0

Answer:

E = 29.7× 10⁻²⁰  j

Explanation:

Given data;

Frequency of light = 4.48 × 10¹⁴ Hz

Energy of photon = ?

Solution:

Formula:

E = h.f

E = energy of photon

h = planck's constant

f = frequency

E = h.f

E = 6.63 × 10⁻³⁴ Kg.m² /s × 4.48 × 10¹⁴ s⁻¹

E = 29.7× 10⁻²⁰ Kg.m²/s²

Kg.m²/s² = j

E = 29.7× 10⁻²⁰  j

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3 years ago
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lapo4ka [179]
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ΔG° = - RT ㏑ K 

when ΔG° is Gibbs free energy 

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and when K = 4.4 x 10^-2

so, by substitution:

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b) then, to get E
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