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DIA [1.3K]
3 years ago
9

When you push down on a block resting on a table, block atoms and table atoms that are in contact with one another

Chemistry
1 answer:
poizon [28]3 years ago
8 0
Option D. maintain their positions.

Pressure does not modify the relative position of the atoms in solid matter. The atoms are kept in position by the atomic and molecular bonds  whose length is a feature of every pair of atoms.

For example, all the bonds of C-C and C-H in the wood will have the same bond length
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FILL IN THE BLANKWORD BANK (can use more than once): less, increases, decreases, greaterNO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)1.Disturbin
Jlenok [28]

Explanation:

If we have the following reaction at equilibrium:

<em>                                           aA + bB ⇄ cC + dD</em>

where a, b, c, and d are the stoichiometric coefficients for the reacting species A, B,  C, and D. For the reaction at a particular temperature:

                       Kc=([C]^c *[D]^d)/([A]^a *[B]^b)

where Kc is the equilibrium constant, which holds that <em>for a reversible reaction at equilibrium  and a constant temperature, a certain ratio of reactant and product concentrations has  a constant value, Kc</em> (the equilibrium constant). Note that although the concentrations  may vary, as long as the reaction in in equilibrium and temperatura don't change, the value of <u>K remains constant.</u>

For reactions that have not reached equilibrium, we obtain the reaction quotient (Qc), instead of the equilibrium  constant <u>by substituting the initial concentrations into the equilibrium constant expression.</u>

                        Qc=([Co]^c *[Do]^d)/([Ao]^a *[Bo]^b)

To determine the direction in wich the net reaction will proceed to reach equilibrium, que compare the values of Qc and Kc.

  • Qc < Kc: To reach equilibrium, reactants must be converted to products (→)
  • Qc = Kc: The initial concentrations are equilibrium concentrations. The system in at equilibrium.
  • Qc > Kc: To reach equilibrium, products must be converted to reactants (←)

Solution:

We have the following reaction:

                             NO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)

So:

Kc=([NOCl]^1*[NO2]^1)/([NO2Cl]^1 *[NO]^1)

     =([NOCl][NO2])/([NO2Cl][NO])  

1. In the equation above, [NO2Cl] it's in the denominator, so if we increase it's numericall value by adding NO2Cl <u>decreases Qc  to a value less than Kc.</u>

<em>(From the chemical point of view, if we disturb the equilibrium adding NO2Cl (a reactant), to reach equilibrium again the system proceeds from left to right (→) consuming this reactant.)</em>

2. To reach a new state of equilibrium (<em>where Qc = Kc</em>), Qc therefore  increases wich means that the denominator of the expression for Qc  decreases <em>(in order to increase the denominator as mention above).</em>

3. To accomplish this, the concentration of reageants decreases <em>(reagents are being consumed), </em>and the concentration of prodcuts increases <em>(products are being formed).</em>

4 0
3 years ago
How are all atoms similar?
attashe74 [19]

Answer:

A. They can not be divided.

Thank you.

BY GERALD GREAT.

5 0
3 years ago
Can someone please help me
Margarita [4]

I think it is the first choice

Hope that helped!

5 0
3 years ago
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Which choice best describes how the Grand Canyon formed?
Mkey [24]
C - Rivers flowing over a long period of time...
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3 years ago
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G Isopropyl methyl ether is slightly soluble with water because the oxygen atom of ethers with or fewer carbon atoms can form a
Inga [223]

Answer:

True

Explanation:

The isopropyl methyl ether is a polar molecule because its dipole moment is different from 0. The ether is formed by a molecule of oxygen between carbons, in this case, the oxygen is bonded to an isopropyl, which has 3 carbons, and to a methyl, with only one carbon, so, the dipole, which is the polar difference between the atoms, will be stronger in the isopropyl bond.

Because of that, the oxygen will have a partial negative charge. The water is also a polar substance, and "like dissolve like". Because water has a dipole in the hydrogen and in the oxygen, the hydrogen of it may bond with the oxygen of the ether, forming a hydrogen bond, which is strong.

5 0
3 years ago
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