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Andrew [12]
3 years ago
12

In a voltaic cell, the salt bridge acts to:

Chemistry
2 answers:
AleksAgata [21]3 years ago
6 0
<span>Provide a direct contact between the oxidation and reduction electrodes - A</span>
Murljashka [212]3 years ago
5 0

The salt bridge acts to maintain a constant ion concentration for both of the half-cells. The anions are moving toward the oxidation side and the cations are moving toward the reduction side via the salt bridge.

Therefore the answer is C- provide constant overall balanced concentration of ions.

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How much money do you guys make off of this lame website?
MrRissso [65]

Answer:

so far from what i've seen its been 80 mil

Explanation:

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7 0
3 years ago
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A solution has a pH of 2.5. Answer the following questions.
olga_2 [115]
PH + pOH = 14  ⇒  pOH = 14 - pH
pOH = 14 - 2.5
pOH = 11.5

[H⁺] = 10^(-pH) = 10^(-2.5)
[H⁺] = 0.003 M
[OH⁻] = 10^(-pOH) = 10^(-11.5) = 3 × 10⁻¹² M
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6 0
3 years ago
Is melting sugar a chemical or physical change? Please provide an explanation
liraira [26]

Answer:

Hola Amigo! Here's Ur Answer :D

Explanation:

The chemical reaction we are most familiar with is that of melting: sugar decomposes at a temperature ranging between 184 and 186°C. This is a very recent discovery we owe to a team of researchers in Illinois. Basically, when we heat sucrose gently, this produces a phenomenon known as “ apparent melting ”.

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3 0
3 years ago
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How many grams of hcl is dissolved in 500 ml of a 0.2 m hcl solution?
umka21 [38]
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7 0
3 years ago
An unknown compound contains 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen by mass. A mass spectrometry analysis reveals that
tiny-mole [99]

Answer:

Molecular formula is C₂₆H₃₆O₄

Explanation:

The compound is 75.69 % C, 8.80 % H and 15.51 % O. This data means, that in 100 g of compound we have 75.69 g, 15.51 g and 8.80 g of, C, O and H, respectively. We know the molar mass of the compound, so we can work to solve the moles of each element.

In 100 g of compound we have 75.69 g C, 15.51 g O and 8.80 g H

In 412 g of compound we would have:

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(412 . 15.51) / 100 = 63.9 g of O

(412 . 8.80) / 100 = 36.2 g of H

Now, we can determine the moles of each, that are contained in 1 mol of compound.

312 g / 12 g/mol 26 C

64 g / 16 g/mol = 4 O

36 g / 1 g/mol = 36 H

Molecular formula is C₂₆H₃₆O₄

4 0
3 years ago
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