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Snezhnost [94]
3 years ago
13

An upright cylindrical tank with radius 6 m is being filled with water at a rate of 2 m3/min. how fast is the height of the wate

r increasing?if h is the water's height, the volume of the water is v = πr2h. we must find dv/dt. differentiating both sides of the equation gives
Chemistry
1 answer:
irina1246 [14]3 years ago
5 0
<span>Volume = pir^2h = 36pih Derivative = 36pi dh/dt v' = 2 m^3/min 2 = 36pi dh/dt dh/dt = 0.0177 m/min.</span>
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A molecule of H2SO4 contains how many atoms?
Margaret [11]

Answer:

2 hydrogen atom, 1 sulfer atom, and 4 oxygen atoms.

6 0
2 years ago
In an experiment, 3.25 g of NH3 are allowed to react with 3.50 g of O2. 4NH3 + 5O2 &gt; 4NO + 6H2O a. Which reactant is the limi
cluponka [151]

Answer:

2.61 g of NO will be formed

The limiting reagent is the O₂

Explanation:

The reaction is:

4NH₃  +  5O₂  →  4NO  +  6H₂O

We convert the mass of the reactants to moles:

3.25g / 17 g/mol = 0.191 moles of NH₃

3.50g / 32 g/mol =0.109 moles of O₂

Let's determine the limiting reactant by stoichiometry:

4 moles of ammonia react with 5 moles of oxygen

Then, 0.191 moles of ammonia will react with (0.191 . 5) / 4 = 0.238 moles of oxygen. We only have 0.109 moles of O₂ and we need 0.238, so as the oxygen is not enough, this is the limiting reagent

Ratio with NO is 5:4

5 moles of oxygen produce 4 moles of NO

0.109 moles will produce (0.109 . 4)/ 5 = 0.0872 moles of NO

We convert the moles to mass, to get the answer

0.0872 mol . 30g / 1 mol = 2.61 g

7 0
3 years ago
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Answer:

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Explanation:

7 0
3 years ago
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