Mass, m=22 kg
It is given that Force, F = 88N
Acceleration, a=4 m/s 2
Answer:
Tension, T = 2038.09 N
Explanation:
Given that,
Frequency of the lowest note on a grand piano, f = 27.5 Hz
Length of the string, l = 2 m
Mass of the string, m = 440 g = 0.44 kg
Length of the vibrating section of the string is, L = 1.75 m
The frequency of the vibrating string in terms of tension is given by :





T = 2038.09 N
So, the tension in the string is 2038.09 N. Hence, this is the required solution.
Answer:10 km westExplanation:he go 40 east then 50 west 50-40 is 10 so he displaces 10 km and as west is more than east in terms of km so we will say that it's 10 km west pls mark as brainliest thanks
Answer:
There is no actual question attached to this, to get a real answer be sure to include the documents/question that is provided on your work.
Explanation:
8.05 that is the answer lllllllll