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BARSIC [14]
3 years ago
9

A student completed a lab report. Which correctly describes the difference between the "Question" and "Hypothesis" sections

Physics
2 answers:
galben [10]3 years ago
4 0

Answer:

the second one!

Explanation:

the question is well, the question, a hypothesis is an educated guess on what you think will be the outcome

kramer3 years ago
4 0

Answer:

The Answer Is B. On Edge

Explanation:

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A solid sphere has a radius of 0.200 m and a mass of 150.0 kg. how much work is required to get the sphere rolling with an angul
Allisa [31]

Here in this case we can use work energy theorem

As per work energy theorem

Work done by all forces = Change in kinetic Energy of the object

Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.

Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

KE = \frac{1}{2}Iw^2 +\frac{1}{2} mv^2

also we know that

I = \frac{2}{5}mR^2

w= \frac{v}{R}

Now kinetic energy is given by

KE = \frac{1}{2}(\frac{2}{5}mR^2)w^2 +\frac{1}{2} m(Rw)^2

KE = \frac{1}{5}mR^2w^2 +\frac{1}{2} mR^2w^2

KE = \frac{7}{10}mR^2w^2

KE = \frac{7}{10}*150*(0.200)^2(50)^2

KE = 10500 J

Now by work energy theorem

Work done = 10500 - 0 = 10500 J

So in the above case work done on sphere is 10500 J

7 0
3 years ago
Based on molecular orbital theory, the only molecule in the list below that has unpaired electrons is ________.
xenn [34]
The answer is Radicals.
6 0
2 years ago
Name two ways to reduce friction and two ways to increase it.
Maurinko [17]
Ways to increase friction 

<span>- increase the roughness of the contact materials </span>
<span>- increase the pressure on the contact </span>


<span>Ways to decrease friction </span>

<span>- float the moving body on air </span>
<span>- suck out any air </span>
4 0
2 years ago
Helppppppppppppppppppppppppppp
geniusboy [140]

Answer:

Car 2 is travelling in a much higher speed than Car 1.But they are travelling or meeting in the same acceleration

7 0
3 years ago
A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, wha
tigry1 [53]

work done = force * distance moved (in direction of the force)

force= mass* acceleration 

force=58.1N

58.1*(5.8*10^4)
=3,369,800 J
3 0
3 years ago
Read 2 more answers
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