If element X has 64 protons, how many electrons does it have?

An individual carries a heterozygote (two diff alleles on same gene) which will be located:

swat32

Answer:

B) On the same place on the same chromosome.

Explanation:

Both alleles are located on the same chromosome and present at the same place because genes come in pair. Each pair of gene is located at a specific place on a chromosome. If the two alleles present at a specific location are similar to each other, it is called homo-zygous while on the other hand, if both alleles are different from one another, they are considered as hetero-zygous.

6 0

3 years ago

In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2

Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

$r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

$r = \frac{1500 - 750}{1995 - 1985} = 750/10 = 75$

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

$r = \frac{D(1995) - D(1885)}{1995 - 1985} = \frac{6 pines/ha - 3pines/ha}{10} = 0.3 pines/ha$

So, on average, each year the number of pines per hectare increases by 0.3

7 0

3 years ago

Importance of cellulose and hemicellulose in industrial purposes?

alukav5142 [94]

Explanation:

Cellulose, hemicellulose and lignin form structures called microfibrils, which are organized into macrofibrils that mediate structural stability in the plant cell wall.

The most important biological role of hemicelluloses is their contribution to strengthening the cell wall by interaction with cellulose and, in some walls, with lignin.

8 0

3 years ago

What is the harmful impact the use of insecticide has on the environment

zimovet [89]

Well the insects eat the plant and the small animals eat the insects and so on.if the insects die the food chain is broken.

4 0

3 years ago

Round seeds and yellow seed color are dominant to wrinkled seeds and green seed color. What is the probability of having offspri

adoni [48]

Answer:

<h2>The probability of a cross between RRYY x RrYy to generate a yellow and wrinkled seed offspring is 0%.</h2>

Explanation:

Circular and yellow seeds are overwhelming and wrinkled and green seeds are passive. It is vital to keep in mind that resective characteristics are as it were displayed when the sibling has two passive alleles for those characteristic, in the event that the descendant includes a latent allele and a overwhelming allele, the characteristic that will be presented is the overwhelming one. For this reason, able to say that a cross between RRYY x RrYy plants, would not create any descendant with wrinkled and yellow seeds. Typically since, the descendant of a crossing, must show an allele of each parent. One parent as it were has overwhelming alleles (RRYY), so able to say that all descendant will get 1 overwhelming allele for color and a overwhelming allele for seed surface, anticipating the sibling from communicating latent characteristics.

7 0

3 years ago