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Mice21 [21]
3 years ago
11

Light of a certain color has a wavelength of 4.8 x 10-7m. Determine the frequency and color of the light wave.

Physics
1 answer:
cluponka [151]3 years ago
3 0

The frequency is 6.3\cdot 10^{14} and it is blue light

Explanation:

The relationship between the speed, the frequency and the wavelength of an electromagnetic wave is given by:

c=f \lambda

where

c=3.0\cdot 10^8 m/s is the speed of light

f is the frequency of the wave

\lambda is its wavelength

In this problem, the wavelength of the wave is

\lambda = 4.8\cdot 10^{-7} m

Therefore, its frequency is:

f=\frac{c}{\lambda}=\frac{3.0\cdot 10^8}{4.8\cdot 10^{-7}}=6.3\cdot 10^{14} Hz

The wavelength of this wave is

\lambda = 480 nm

And by looking at the table of the wavelengths of the colors, we notice that this corresponds to the blue light, which has a range of wavelength of

[450 - 495] nm

Learn more about waves and electromagnetic waves here:

brainly.com/question/5354733

brainly.com/question/9077368

brainly.com/question/9184100

brainly.com/question/12450147

#LearnwithBrainly

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Read 2 more answers
A uniform, 4.5 kg, square, solid wooden gate 2.0 mm on each side hangs vertically from a frictionless pivot at the center of its
True [87]

Answer:

The angular velocity is  w = 1.43\  rad/sec

Explanation:

From the question we are told that

   The  mass of wooden gate  is m_g = 4.5 kg

    The  length of side is  L = 2 m

    The mass of the raven is  m_r = 1.2 kg

     The initial speed of the raven is u_r = 5.0m/s

     The final speed of the raven is   v_r = 1.5 m/s

From the law of  conservation of angular momentum we express this question mathematically as

       Total initial angular momentum  of both the Raven and  the Gate =  The Final angular momentum of both the Raven and the Gate  

The initial angular momentum of the Raven is m_r * u_r * \frac{L}{2}

Note: the length is half because the Raven hit the gate at the mid point

The initial angular momentum of the Gate is  zero

Note: This above is the generally formula for angular momentum of  square objects

  The final angular velocity  of the Raven is  m_r * v_r * \frac{L}{2}

   The  final angular velocity of the Gate  is   \frac{1}{3} m_g L^2 w

Substituting this formula

  m_r * u_r * \frac{L}{2}  =   \frac{1}{3} m_g L^2 w + m_r * v_r * \frac{L}{2}

  \frac{1}{3} m_g L^2 w   =    m_r * v_r * \frac{L}{2} -   m_r * u_r * \frac{L}{2}

  \frac{1}{3} m_g L^2 w   =    m_r *  \frac{L}{2} * [u_r - v_r]

Where w is the angular velocity

     Substituting value  

   \frac{1}{3} (4.5)(2)^2  w   =    1.2 *  \frac{2}{2} * [5 - 1.5]

     6w = 4.2

       w = \frac{6}{4.2}

            w = 1.43\  rad/sec

5 0
2 years ago
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