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4 years ago

Why is density and the melting point both substances of mass

1 answer:

3 0

Density is mass over volume. Density is also a charecteristic property wich defines a substance and two different substance cant have the same charasteristic property.

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Which of the following best describes a plane?

ASHA 777 [7]

From that list of choices, choice 'B' is the only example of a plane,
but it doesn't 'describe' it at all.

7 0

4 years ago

Objects are lighter on the moon than they are on earth. if an object A weighs 25lbs on the Moon and another object B weighs 25 N

solong [7]

Answer:

a. Object A

Explanation:

The mass of an object implies the quantity of matter in it, while the weight is the amount of gravitational force applied on an object.

The object A has a mass of 25 lbs, but object B on the earth has a weight, W, of 25 N.

So that,

For object A on the moon, mass = 25 lbs

For object B on the earth, W = 25 N,

W = m x g

25 = m x 10 (g = 10 m/ $s^{2}$ )

m = $\frac{25}{10}$

= 2.5 lbs

Mass of object B is 2.5 lbs.

Therefore, the mass of the object A is more than that of B.

5 0

3 years ago

When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37Â° C) by warmi

Gelneren [198K]

Answer:

7.72 Liters

Explanation:

normal body temperature = T_body =37° C

temperature of ice water = T_ice =0°c

specfic heat of water = c_{water} =4186J/kg.°C

if the person drink 1 liter of cold water mass of water is = m = 1.0kg

heat lost by body is Qwater =mc_{water} ΔT

= mc{water} ( T_ice - T_body)

= 1.0×4186× (0 -37)

= -154.882 ×10^3 J

here negative sign indicates the energy lost by body in metabolic process energy expended due to brisk - hour long walk is Q_{walk} = 286 kilocalories

= 286×4186J

so number of liters of ice water have to drink is

n×Q_{water} =Q_{walk} n= Q_{walk}/ Q_{water}

= 286×4186J/154.882×10^3 J

= 7.72 Liters

7 0

3 years ago

Read 2 more answers

THE PROBLEM!

Elodia [21]

Answer: 15.29

Explanation: there you go have a nice day (*^p^*)

3 0

3 years ago

When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to

Serjik [45]

Answer:

E) d/sqrt2

Explanation:

The initial electric force between the two charge is given by:

$F=k\frac{q_1 q_2}{d^2}$

where

k is the Coulomb's constant

q1, q2 are the two charges

d is the separation between the two charges

We can also rewrite it as

$d=\sqrt{k\frac{q_1 q_2}{F}}$

So if we want to make the force F twice as strong,

F' = 2F

the new distance between the charges would be

$d'=\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{1}{\sqrt{2}}\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{d}{\sqrt{2}}$

so the correct option is E.

8 0

3 years ago