Answer:
37.8 m
Explanation:
At point 0, the ball is at height y₀.
At point 1, the ball is at height 30 m.
At point 2, the ball is at height 0 m.
Given:
y₁ = 30 m
y₂ = 0 m
v₀ = 0 m/s
a = -10 m/s²
t₂ − t₁ = 1.5 s
Find: y₀
Use constant acceleration equation.
y = y₀ + v₀ t + ½ at²
Evaluate at point 1.
y₁ = y₀ + v₀ t₁ + ½ at₁²
30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²
30 = y₀ − 5t₁²
Evaluate at point 2.
y₂ = y₀ + v₀ t₂ + ½ at₂²
0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²
0 = y₀ − 5t₂²
y₀ = 5t₂²
Substitute:
y₀ = 5 (1.5 + t₁)²
y₀ = 5 (2.25 + 3t₁ + t₁²)
y₀ = 11.25 + 15t₁ + 5t₁²
30 = 11.25 + 15t₁ + 5t₁² − 5t₁²
30 = 11.25 + 15t₁
t₁ = 1.25
30 = y₀ − 5t₁²
30 = y₀ − 5(1.25)²
y₀ ≈ 37.8
Answer:
Assume that the planet <em>has a defined angular momentum (this is not true due to tidal friction). So if mass is farther away from the center of mass it will have more angular momentum, and if mass is near you will have more angular momentum.</em>
If the mass is similar to the center of mass and slower if the mass is farther from the center of mass, an object will spin faster to combat this. Building skyscraper will also slow down the earth and dropping leaves will raise the angular velocity.
A great example of this is with figure skaters, when they want to spin faster they tuck themselves in tightly, bringing more mass close to the center of mass which increases angular velocity there.
Answer:
an inverse relationship
Explanation:
As you increase in elevation, there is less air above you thus the pressure decreases. As the pressure decreases, air molecules spread out further (i.e. air expands) and the temperature decreases. If the humidity is at 100 percent (because it's snowing), the temperature decreases more slowly with height.
1 is A I believe. Pretty sure
Since the temperature is 71 degree, the scale of measurement is Fahrenheit scale.
For converting Fahrenheit scale to Kelvin scale we have the formula.
Here 
So, 
Outside temperature in kelvin scale 
