Explanation:
this is the answer.....................
.
Answer:(a) 4775.2Hz (b) 4.06m/s (c) 19382.15m/s²
Explanation: Given that the frequency of oscilation f, is 760Hz and the maximum displacement x, is 0.85mm= 0.00085m
(a) Angular frequency w= 2πf
w= 2π × 760 = 4775.2Hz
(b) Maximum speed v is given as the product of angular frequency and maximum displacement
V=wx
V= 4775.2 × 0.00085
V= 4.06m/s
(c) The maximum acceleration a
= w²x
= (4775.2)² × (0.00085)
a= 19382.15m/s².
Answer:
31.8 m in the positive x-direction
Explanation:
Here we have an example of multiplication of a vector by a scalar.
In order to perform this operation, we have to:
- multiply the magnitude of the vector by the scalar
- reverse the direction of the vector if the scalar is a negative number
In this problem, the original vector has a lenght of 8.6 m and it points in the negative x direction. Now we have to find the vector -3.7A, so we have:
- The magnitude is obtained by calculating the product

- The direction is reversed, because the scalar is -3.7, so the new vector will point in the positive x-direction
So the final vector is 31.8 m in the positive x-direction, and therefore its x-component is also 31.8 m in the positive direction.
<span>The electromagnet in a Galvanometer moves a pointer
along a numbered scale in response to a current. </span>