A lound sound has large

.Why does the tension in each chain of a

anyanavicka [17]

Because if your putting tension on something tensions obviously going to increase with more pressure and weight on it

7 0

2 years ago

There is a filing cabinent that is 52 in. tall and 15 in. wide. The center of gravity of the cabinet is right at the center. To

erastova [34]

Answer:

16 degrees

Explanation:

The tipping point of the cabinet is sketched below.

5 0

1 year ago

A pool ball moving 1.83 m/s strikes an identical ball at rest. Afterward, the first ball moves 1.15 m/s at a 23.3 degrees angle.

chubhunter [2.5K]

Answer:

v_{1fy} = - 0.4549 m / s

Explanation:

This is an exercise of conservation of the momentum, for this we must define a system formed by the two balls, so that the forces during the collision have internal and the momentum is conserved

initial. Before the crash

p₀ = m v₁₀

final. After the crash

$p_{f}$ = m $v_{1f}$ + m v_{2f}

Recall that velocities are a vector so it has x and y components

p₀ = p_{f}

we write this equation for each axis

X axis

m v₁₀ = m v_{1fx} + m v_{2fx}

Y Axis

0 = -m v_{1fy} + m v_{2fy}

the exercise tells us the initial velocity v₁₀ = 1.83 m / s, the final velocity v_{2f} = 1.15, let's use trigonometry to find its components

sin 23.3 = v_{2fy} / v_{2f}

cos 23.3 = v_{2fx} / v_{2f}

v_{2fy} = v_{2f} sin 23.3

v_{2fx} = v_{2f} cos 23.3

we substitute in the momentum conservation equation

m v₁₀ = m v_{1f} cos θ + m v_{2f} cos 23.3

0 = - m v_{1f} sin θ + m v_{2f} sin 23.3

1.83 = v_{1f} cos θ + 1.15 cos 23.3

0 = - v_{1f} sin θ + 1.15 sin 23.3

1.83 = v_{1f} cos θ + 1.0562

0 = - v_{1f} sin θ + 0.4549

v_{1f} sin θ = 0.4549

v_{1f} cos θ = -0.7738

we divide these two equations

tan θ = - 0.5878

θ = tan-1 (-0.5878)

θ = -30.45º

we substitute in one of the two and find the final velocity of the incident ball

v_{1f} cos (-30.45) = - 0.7738

v_{1f} = -0.7738 / cos 30.45

v_{1f} = -0.8976 m / s

the component and this speed is

v_{1fy} = v1f sin θ

v_{1fy} = 0.8976 sin (30.45)

v_{1fy} = - 0.4549 m / s

8 0

2 years ago

Indicate whether each of the following statements is true or false. In a coal-fired power plant, chemical energy is first conver

denis23 [38]

Answer:

1. In a coal-fired power plant, chemical energy is first converted to thermal energy. TRUE.

The chemical energy in the coal is converted to thermal energy when the coal is burnt to produce steam.

2. In a coal-fired power plant, approximately 2/5 of original energy in the coal is lost to heat. FALSE.

Approximately 3/5 of the original energy is lost not 2/5 so this statement is false.

3. The molecules in cold air move faster than in hot air. FALSE.

Molecules with more heat move faster than molecules with less. Molecules in cold air therefore, will move slower than molecules in hot air.

6 0

2 years ago

1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.

AURORKA [14]

Answer:

a) Please find attached the required drawing of light passing through the lens

By the use of similar triangles;

The image distance from the lens = 26 cm

The height of the image = 14 cm

c) The image distance from the lens = 26 cm

The height of the image = 14 cm

Explanation:

Question;

a) Determine the image distance and the height of the image

b) Calculate the image position and height

The given parameters are;

The height of the object, h = 14 cm

The distance of the object from the mirror, u = 26 cm

The focal length of the mirror, f = 13 cm

The location of the object = 2 × The focal length

Therefore, given that the center of curvature ≈ 2 × The focal length, we have;

The location of the object ≈ The center of curvature of the lens

The diagram of the object, lens and image created with MS Visio is attached

From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m

The height of the image = The height of the object - 14 cm

b) The lens equation is used for finding the image distance from the lens as follows;

$\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}$

Where;

v = The image distance from the lens

We get;

$v = \dfrac{u \times f}{u - f}$

Therefore;

$v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26$

The distance of the image from the lens, v = 26 cm

The magnification, M =v/u

∴ M = 26/26 = 1, therefore, the object and the image are the same size

Therefore;

The height of the image = The height of the object = 14 cm.

5 0

2 years ago