(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
where
L is the wire length
T is the tension
m is the wire mass
In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
b) The frequency of the nth-harmonic for a standing wave in a wire is given by
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
c) Similarly, the third lowest frequency (third harmonic) is given by
Answer:
Explanation:
a )
Frequency n = 450 x 10⁶ .
20 light years = 20 x 9.461 x 10¹⁵m
Let power of source be P
Intensity at distance R = 
Substituting the given values
8.5 x 10⁻¹⁰ = 
P = 3822457 x 10²⁰ W.
b )
Half the power will be from electric and half will be from magnetic field.
Total power = 8.5 x 10⁻¹⁰ W
Half = 4.25 x 10⁻¹⁰ W .
power of electric field
= 
ε is permittivity , E₀ is amplitude of electric field , c is velocity of light .
Putting the values
4.25 x 10⁻¹⁰ = .5 x 8.85 x 10⁻¹² x E² x 3 x 10⁸
E₀² = .32 x 10⁻⁶
E₀ = .565 x 10⁻³ W / s .
Answer:
a) w = 25.1 rad/s, b) θ = 0.9599 rad
, c) α = 328.1 rad/s² d) t= 0.0765 s
Explanation: Let's work on this exercise with the equations of angular kinematics
a) The angular velocity is
w = 4.00 rev / s (2π rad / 1 rev)
w = 25.1 rad/s
b) let's reduce the angle of degrees to radians
θ = 55 ° (π rad / 180 °)
θ = 0.9599 rad
c) Let's use the initial angular velocity as the system part of the rest is zero
w² = w₀² + 2 α θ
α = w² / 2 θ
α = 25.1²/2 0.9599
α = 328.1 rad / s²
d)
w = w₀ + α t
t = w / α
t = 25.1 / 328.1
t= 0.0765 s
Answer:
electron
Explanation:
The energy for particle in a box is given by:
for the system in ground state, n =1
Since, the boxes are identical, L is same for all the three particles.
h is Planck's constant.
Since energy is inversely proportional to wavelength, therefore
Thus, electron has the longest wavelength.
Answer:
Kindly check explanation
Explanation:
The total displacement between 0 seconds and 16second will be :
Final position (Xf) after 16 seconds = 0 m
Initial position(Xi) at 0 seconds = 12 m
(Xf - Xi) = 12m
The total distance traveled between 0 seconds and 16 seconds will be :
Vertical Distance traveled = 12 meters
