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quester [9]
3 years ago
12

A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Teflon frying p

an is only 0.400 N. Knowing the coefficient of kinetic friction between the two materials (0.04), he quickly calculates the normal force. What is it (in N)? N
Physics
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

normal force = 10 N

Explanation:

Given data

frictional force = 0.400 N

coefficient of kinetic friction = 0.04

Solution

we get here normal force that is express as

normal force = \frac{Frictional\ force}{coefficient\ of\ friction}        ............1

put here value and we will get value

normal force = \frac{0.400}{0.04}  

solve it we get

normal force = 10 N

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A 20 kg wombat climbs 10 m up a tree. When it stops what is the wombats gravitational potential energy?
swat32

Answer:

2000J

Explanation:

PE = m*g*h

PE= 20kg*10m/s^-2*10m

PE= 2000J

5 0
4 years ago
What is the equivalent resistance of the
BigorU [14]

Answer:

Approximately 111\; {\rm \Omega}.

Explanation:

It is given that R_{1} = 200\; {\Omega} and R_{2} = 250\; {\Omega} are connected in a circuit in parallel.

Assume that this circuit is powered with a direct current power supply of voltage V.

Since R_{1} and R_{2} are connected in parallel, the voltage across the two resistors would both be V. Thus, the current going through the two resistors would be (V / R_{1}) and (V / R_{2}), respectively.

Also because the two resistors are connected in parallel, the total current in this circuit would be the sum of the current in each resistor: I = (V / R_{1}) + (V / R_{2}).

In other words, if the voltage across this circuit is V, the total current in this circuit would be I = (V / R_{1}) + (V / R_{2}). The (equivalent) resistance R of this circuit would be:

\begin{aligned} R &= \frac{V}{I} \\ &= \frac{V}{(V / R_{1}) + (V / R_{2})} \\ &= \frac{1}{(1/R_{1}) + (1 / R_{2})}\end{aligned}.

Given that R_{1} = 200\; {\Omega} and R_{2} = 250\; {\Omega}:

\begin{aligned} R &= \frac{1}{(1/R_{1}) + (1 / R_{2})} \\ &= \frac{1}{(1/(200\: {\rm \Omega})) + (1/(250\; {\rm \Omega}))} \\ &\approx 111\; {\rm \Omega}\end{aligned}.

7 0
2 years ago
A large ball of gas that is held together by gravity and that has a core so hot that
valentina_108 [34]
The answer is a star
4 0
2 years ago
A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of mpiston = 2 kg and a cross-secti
BlackZzzverrR [31]
<h2>Answer:</h2>

105146 Pa

<h2>Explanation:</h2>

1) We will make a Free-Body Diagram representing all the upward and downward pressures exerted on the piston.

  • Downward Pressures:
  1. Pressure exerted by the compressed spring (Pspring)
  2. Pressure due to weight of the piston (Pw)
  3. Atmospheric pressure (Patm)  
  • Upward Pressures:  
  1. Initial pressure inside the cylinder. (P1)              

2) We will formulate an equation balancing all upward and downward pressures.

     P1= Patm + Pw + Pspring

3) We will calculate each of the pressures separately.

  • Pspring

          P = F/A

          F= ks

          k= 38×1000 =38000 N m

          s= 2.5 /1000 = (2.5x10^-3) m

          F = 38000×(2.5x10^-3) = 95 N

          A = 30/10000 = (30x10^-4) m2

          P = 95 / (30x10^-4)

          Pspring ≅ 3167 Pa

  • Pw

          P = F/A

          F = W = mg

          W = 2×9.81 = 19.62 N

          A = 30/10000 = (30x10^-4) m2

          P = 19.62 / (30x10^-4)

          Pw = 654 Pa

  • Patm

        P = 1atm = 101325 Pa

        Patm = 101325 Pa

4) We will add all the downward pressures to reach the final answer (initial pressure inside the cylinder).

       P1= Patm + Pw + Pspring

       P1= 101325+654+3167

       P1= 105146 Pa

8 0
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The formation of atp as a result of the activity of the electron transport system is termed substrate-level phosphorylation is c
Zigmanuir [339]

Answer:

Oxidative phosphorylation

Explanation:

This takes place mostly in the organelle called the mitochondrion.

Oxidation of nutrients in cells by enzymes results in the release of the chemical energy present in the molecular energy.

The NADH and succinate products of the citric acid cycle are also oxidized. All this series of reactions takes place in the Electron transport system.The energy from the oxidation is used to produce adenosine triphosphate (ATP) hence the name oxidative phosphorylation.

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