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Andru [333]
3 years ago
12

A person applies a force of 200N to move an object initially at rest weighing 400N. What could be the coefficient of static fric

tion between the object and the surface?
Physics
1 answer:
SOVA2 [1]3 years ago
5 0

Answer:

\mu=0.5

Explanation:

Given that,

Applied force, F = 200 N

Weight of the object, or the normal force, N = 400 N

We need to find the coefficient of static friction between the object and the surface.

The force of friction has the same magnitude as that of applied force. It can be given by :

F=\mu mg

mg is weight of the object

\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{200}{400}\\\\\mu=0.5

So, the coefficient of static friction between the object and the surface is 0.5.

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hey guys, l need some help! what is the weight of potatoes of mass 75 kg on the surface of the earth? (g=9.8m/s square) ans=735N
Airida [17]

Answer:

735N

Explanation:

Weight is a measurement of force.

F = Force

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a = acceleration

F = m*a

F = 75kg*9.8m/s²

F = 735N

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The form of energy given off by the vibrating strings of the violin is? A. Electrical Energy B. Potential Energy C. Radiant Ener
S_A_V [24]

Answer:

D . Sound energy

Explanation:

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6 0
3 years ago
If the pressure inside the cylinder increases to 1.6 atm, what is the final volume, in milliliters, of the cylinder?
Bess [88]

This is an incomplete question, here is a complete question.

The air in the cylinder with a piston has a volume of 220 mL and a pressure of 650 mmHg.

If the pressure inside the cylinder increases to 1.6 atm, what is the final volume, in milliliters, of the cylinder?

Answer : The final volume of the cylinder is, 117.6 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure of gas = 650 mmHg = 0.855 atm   (1 atm = 760 mmHg)

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V_1 = initial volume of gas = 220 mL

V_2 = final volume of gas = ?

Now put all the given values in the above equation, we get:

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V_2=117.6mL

Therefore, the final volume of the cylinder is, 117.6 mL

8 0
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