1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andru [333]
3 years ago
12

A person applies a force of 200N to move an object initially at rest weighing 400N. What could be the coefficient of static fric

tion between the object and the surface?
Physics
1 answer:
SOVA2 [1]3 years ago
5 0

Answer:

\mu=0.5

Explanation:

Given that,

Applied force, F = 200 N

Weight of the object, or the normal force, N = 400 N

We need to find the coefficient of static friction between the object and the surface.

The force of friction has the same magnitude as that of applied force. It can be given by :

F=\mu mg

mg is weight of the object

\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{200}{400}\\\\\mu=0.5

So, the coefficient of static friction between the object and the surface is 0.5.

You might be interested in
Help fast!!! I thought I understood but I don’t
cricket20 [7]
The awnswer is c give me brainlest!!!
8 0
3 years ago
Help with 7,8,9 please!!
Marysya12 [62]

# 7 the answer is 4) because you need opposites in order to attract

# 8 I'm going to guess it is 4) because electricity is needed in order a light bolt to work.(don't take my word for this one I'm not sure but, the other answer are correct)

# 9  the answer is 4) because the comb dose collect negative charges from the hair in order to make the hair have positive charge.


Hope this helped : )

4 0
2 years ago
Why is a neutral object attracted to a charged object?
mixas84 [53]
Because electricity attracts like people
7 0
3 years ago
An object located near the surface of Earth has a weight of a 245 N
marusya05 [52]

Answer:

The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.

Explanation:

Weight of the object on the surface of Earth, W = 245 N

On the surface of Earth, acceleration due to gravity, g = 10 m/s²

Weight of an object is given by :

W = mg

m is mass

m=\dfrac{W}{g}\\\\m=\dfrac{245\ N}{10\ m/s^2}\\\\=24.5\ kg

So, the mass of the object is 24.5 kg

Acceleration due to gravity on Mars, g' = 3.72 m/s²

Weight of the object on Mars,

W' =mg'

W' = 24.5 kg × 3.72 m/s²

= 91.14 N

So, the weight of the object on Mars is 91.14 N.

4 0
3 years ago
How long does it take a vehicle to reach a velocity of 32 m/s if it accelerates from rest at a rate of 4.2 m/s^2?
Marta_Voda [28]

Answer:

7.62

Explanation:

because you have to divide 32/4.2

and can you do a friend request so i can accept it

4 0
3 years ago
Other questions:
  • If millikan was measuring the charge on an oil droplet with 3 negatively charged electrons on it, what charge would he have meas
    5·1 answer
  • Identify the direction (from high to low, from low to high) that heat is normally transferred and give an example. (WILL GIVE BR
    12·1 answer
  • A syrup added to an empty container with a mass of 115.25g . When 0.100 pint of syrup is added, the total mass of the container
    14·1 answer
  • The howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 8.9 km. Assume the
    12·1 answer
  • Two objects were lifted by a machine. one object had a mass of 2 kilograms and was lifted at the speed of 2 m/s. the other had a
    13·1 answer
  • A liquid in a given capillary tube always rises up to a fixed height but not infinitely why
    9·1 answer
  • 5.00 kg of liquid water is heated to 100.0 °C in a closed system. At this temperature, the density of liquid water is 958 kg/m3
    12·1 answer
  • Answer the question plz
    15·1 answer
  • A car moves with a velocity of 54km/h to a velocity of 72lm/h for 5 minutes. determine the distance covered
    8·1 answer
  • *Urgent* I WILL GIVE BRAINLIEST
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!