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Andru [333]
3 years ago
12

A person applies a force of 200N to move an object initially at rest weighing 400N. What could be the coefficient of static fric

tion between the object and the surface?
Physics
1 answer:
SOVA2 [1]3 years ago
5 0

Answer:

\mu=0.5

Explanation:

Given that,

Applied force, F = 200 N

Weight of the object, or the normal force, N = 400 N

We need to find the coefficient of static friction between the object and the surface.

The force of friction has the same magnitude as that of applied force. It can be given by :

F=\mu mg

mg is weight of the object

\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{200}{400}\\\\\mu=0.5

So, the coefficient of static friction between the object and the surface is 0.5.

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A closed pipe creates a
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Answer:

375 hz

Explanation:

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3 years ago
Please help, I don’t get the question.
aalyn [17]

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6 0
3 years ago
awhite billiard ball with mass mw = 1.47 kg is moving directly to the right with a speed of v = 3.01 m/s and collides elasticall
pochemuha

Answer:

speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

initial kinetic energy = final kinetic energy

KE = 6.66 J

Explanation:

Since there is no external force on the system of two balls so here total momentum of two balls initially must be equal to the total momentum of two balls after collision

So we will have

momentum conservation along x direction

m_1v_{1i} + m_2v_{2i} = m_1v_{1x} + m_2v_{2x}

now plug in all values in it

1.47 \times 3.01 + 0 = 1.47 v_1cos68 + 1.47 v_2cos22

so we have

3.01 = 0.375v_1 + 0.927v_2

similarly in Y direction we have

m_1v_{1i} + m_2v_{2i} = m_1v_{1y} + m_2v_{2y}

now plug in all values in it

0 + 0 = 1.47 v_1sin68 - 1.47 v_2sin22

so we have

0 = 0.927v_1 - 0.375v_2

v_2 = 2.47 v_1

now from 1st equation we have

3.01 = 0.375 v_1 + 0.927(2.47 v_1)

v_1 = 1.13 m/s

v_2 = 2.78 m/s

so speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

Also we know that since this is an elastic collision so here kinetic energy is always conserved to

initial kinetic energy = final kinetic energy

KE = \frac{1}{2}(1.47)(3.01^2)

KE = 6.66 J

5 0
4 years ago
A wooden block meauring 40cm x 10cm x 5cm has a mass 850gm . find the density of wood?
Lelechka [254]

Answer:

Explanation:

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3 years ago
Jake has four pairs of horseshoe magnets in different sizes. He experiments by moving each pair farther and farther apart. Which
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Answer:

a)  the largest pair of magnets

this is the answer

Explanation:

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