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ludmilkaskok [199]
3 years ago
6

What is the primary atomic characteristic that Mendeleev used to organize the periodic table?

Physics
2 answers:
Fudgin [204]3 years ago
7 0
Atomic number is the answer
Svet_ta [14]3 years ago
6 0

Atomic mass is the primary atomic characteristic that Mendeleev used to organize the periodic table.

 

<span>The </span>atomic mass<span> (ma) is the </span>mass<span> <span>of an </span></span>atomic<span> particle, sub-</span>atomic<span> <span>particle, or molecule. It is commonly expressed in unified </span></span>atomic mass<span> units (u) where by international agreement, 1 unified </span>atomic mass<span> <span>unit is defined as 1/12 of the </span></span>mass<span> <span>of a single carbon-12 </span></span>atom<span> (at rest).</span>

 

The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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1.41 m/s^2

Explanation:

First of all, let's convert the two speeds from km/h to m/s:

u = 94.0 km/h \cdot \frac{1000 m/km}{3600 s/h} = 26.1 m/s

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Now we find the centripetal acceleration which is given by

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we also have a tangential acceleration, which is given by

a_t = \frac{v-u}{t}

where

t = 17.0 s

Substituting values,

a_t=\frac{12.8 m/s-26.1 m/s}{17.0 s}=-0.78 m/s^2

The two components of the acceleration are perpendicular to each other, so we can find the resultant acceleration by using Pythagorean theorem:

a=\sqrt{a_c^2+a_t^2}=\sqrt{(1.17 m/s^2)+(-0.78 m/s^2)}=1.41 m/s^2

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