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forsale [732]
3 years ago
9

A bungee cord with a spring constant of 800 stretches 6 meters at its greatest displacement. How much elastic potential energy d

oes the bungee cord have? The bungee cord has 9600 ⇒ 14,400 J of elastic potential energy.
Physics
1 answer:
Vinil7 [7]3 years ago
4 0

Elastic potential energy is given by formula

U = \frac{1}{2} kx^2

here we know that

k = 800 N/m

x = 6 m

Now using above formula we have

U = \frac{1}{2}(800)(6^2)

U = 14400 J

So elastic potential energy in the chord is 14400 J

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The first statement make more sence
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Physics double pivot question​
andriy [413]

Explanation:

Assuming the wall is frictionless, there are four forces acting on the ladder.

Weight pulling down at the center of the ladder (mg).

Reaction force pushing to the left at the wall (Rw).

Reaction force pushing up at the foot of the ladder (Rf).

Friction force pushing to the right at the foot of the ladder (Ff).

(a) Calculate the reaction force at the wall.

Take the sum of the moments about the foot of the ladder.

∑τ = Iα

Rw (3.0 sin 60°) − mg (1.5 cos 60°) = 0

Rw (3.0 sin 60°) = mg (1.5 cos 60°)

Rw = mg / (2 tan 60°)

Rw = (10 kg) (9.8 m/s²) / (2√3)

Rw = 28 N

(b) State the friction at the foot of the ladder.

Take the sum of the forces in the x direction.

∑F = ma

Ff − Rw = 0

Ff = Rw

Ff = 28 N

(c) State the reaction at the foot of the ladder.

Take the sum of the forces in the y direction.

∑F = ma

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3 0
3 years ago
How much work is done when a porcelain vase with mass of 2.5 kg is lifted up 3 m to a shelf? (HINT- Weight can be used as Force
alexdok [17]
Work = force x distance
F= 2.5
D= 3
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A 2.0 m × 4.0 m flat carpet acquires a uniformly distributed charge of −10 μC after you and your friends walk across it several
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Answer:

The  charge on the dust particle is  q_d  = 6.94 *10^{-13} \  C

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From the question we are told that

    The length is  l = 2.0 \ m

    The width is  w = 4.0 \ m

   The charge is  q =  -10\mu C= -10*10^{-6} \ C

    The mass suspended in mid-air is m_a =  5.0 \mu g =  5.0 *10^{-6} \ g =  5.0 *10^{-9} \  kg

   

Generally the electric field on the carpet is mathematically represented as

           E =  \frac{q}{ 2 *  A  *  \epsilon _o}

Where \epsilon _o is the permittivity of free space with value \epsilon_o = 8.85*10^{-12}  \ \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

substituting values

           E =  \frac{-10*10^{-6}}{ 2 *  (2 * 4 )  *  8.85*10^{-12}}

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Generally the electric force keeping the dust particle on the air  equal to the force of gravity acting on the particles

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=>     q_d *  E  =  m * g

=>      q_d  =  \frac{m * g}{E}

=>      q_d  =  \frac{5.0 *10^{-9} * 9.8}{70621.5}

=>     q_d  = 6.94 *10^{-13} \  C

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These are characteristics of a wave. The amplitude is how high and low the waves go. Crests are high points on the wave, and troughs are low points on the wave.
5 0
3 years ago
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