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forsale [732]
3 years ago
9

A bungee cord with a spring constant of 800 stretches 6 meters at its greatest displacement. How much elastic potential energy d

oes the bungee cord have? The bungee cord has 9600 ⇒ 14,400 J of elastic potential energy.
Physics
1 answer:
Vinil7 [7]3 years ago
4 0

Elastic potential energy is given by formula

U = \frac{1}{2} kx^2

here we know that

k = 800 N/m

x = 6 m

Now using above formula we have

U = \frac{1}{2}(800)(6^2)

U = 14400 J

So elastic potential energy in the chord is 14400 J

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Read 2 more answers
Find the work w1 done on the block by the force of magnitude f1 = 60.0 n as the block moves from xi = -3.00 cm to xf = 1.00 cm
Norma-Jean [14]
By definition, the work done by a force is given by:
 W1 = F1 * d

 Where,
 F: magnitude of force
 d: distance traveled.
 Substituting values we have:
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W1 = 60 * (0.01 - (-0.03))

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W1 = 2.40 J

 Answer: 
 the work w1 done on the block by the force of magnitude f1 = 60.0 n is:
 W1 = 2.40 J
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3 years ago
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