Answer:
q = -2 m and q = -0.5 m
Explanation:
For this exercise we must use the equation of the optical constructor
1 / f = 1 / p + 1 / q
where f is the focal length, p and q are the distance to the object and the image, respectively
Let's start with the far vision point, in this case the power of the lens is
P = -0.5D
power is defined as the inverse of the focal length in meter
f = 1 / D
f = -1 / 0.5
f = - 2m
the object for the far vision point is at infinity p = infinity
1 / f = 1 / p + i / q
1 / q = 1 / f - 1 / p
1 / q = -1/2 - 1 / ∞
q = -2 m
The sign indicates that the image is on the same side as the object
Now let's lock the near view point
D = +2.00 D
f = 1 / D
f = 0.5m
the near mink point is p = 25 cm = 0.25 m
1 / f = 1 / p + 1 / q
1 / q = 1 / f - 1 / p
1 / q = 1 / 0.5 - 1 / 0.25
1 / q = -2
q = -0.5 m
the sign indicates that the image is on the same side as the object in front of the lens
Answer:
I for a rod about its center is I = M L^2 / 12
A = L (1/2 - 1/3) = L / 6 distance from middle to location L/3
A^2 = L^2 / 36
I = M L^2 (1/12 + 1/36) = M L^2 (4 / 36) = M L^2 / 9
I about given location by parallel axis theorem
Answer:
F = 0N
Explanation:
The force between two charges is given by
where r is the distance between the charges and K is the Coulomb's constant
(k=8-89*10^9Nm^2/C^2)
The force in the first charge is only the sum of the forces due to the other charges. Hence we have
Ft=0N
Hope this helps!!
Answer:
I am not a driver, but I think it's C.
Explanation:
Answer:
10.4mm
Explanation:
2 pages = 1 leaf
200 pages = 100 leaves
100 × 0.10 = 10 mm thickness
Total thickness = 2(0.20) +10 = 0.4+10 = 10.4mm
