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hram777 [196]
3 years ago
7

According to newtos first law of motion. what is required to make a object slow down.

Physics
1 answer:
ladessa [460]3 years ago
5 0

Answer:

Friction

Explanation:

Friction is a force that slows down moving objects. If you roll a ball across a shaggy rug, you can see that there are lumps and bumps in the rug that make the ball slow down. The rubbing, or friction, between the ball and the rug is what makes the ball stop rolling. External Force is required.

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If the speed of light in a substance is 2.26 x 10^8 m/s, what is the index of refraction of that substance?
vladimir1956 [14]

Answer:

1.33

Explanation:

speed of light in vacuum, c = 3 x 10^8 m/s

speed of light in medium, v = 2.26 x 10^8 m/s

The refractive index of the medium is given by

μ = speed of light in vacuum / speed of light in medium

μ = (3 x 10^8) / (2.26 x 10^8)

μ = 1.33

4 0
2 years ago
Two identical cylinders at the same pressure contain the same gas. if cylinder a contains three times as much gas as cylinder b,
Alborosie

By ideal gas theory, cylinder b has the higher temperature.

We need to know about the ideal gas theory to solve this problem. The ideal gas can be represented by

P . V = n . R . T

where P is the pressure, V is volume, n is the number of molecules, R is the ideal gas constant and T is temperature.

From the question above, we know that

Pa = Pb = P

na = 3nb

Find the temperature of the cylinder a

P . V = n . R . Ta

Ta = P . V /( na . R )

Substitute na

Ta = P . V /( (3nb) . R )

Ta = (1/3) x (P . V /( (nb . R ))

Find the temperature of the cylinder b

P . V = n . R . Tb

Tb = P . V /( nb . R )

The cylinder a temperature is 3 times smaller than the temperature in cylinder b.

Find more on ideal gas at: brainly.com/question/25290815

#SPJ4

5 0
1 year ago
Two circular holes, one larger than the other, are cut in the side of a large water tank whose top is open to the atmosphere. Ho
lidiya [134]

Answer:\frac{r_1}{r_2}=1.565

Explanation:

Given

two holes are made with different sizes

Hole 1 is large in size and hole 2 is small

If the volume flow rate of water is same for both the hole then small hole must be below the large hole because for same flow rate, velocity of water is large while cross-sectional area is small so it compensate to give same flow for both the holes.

Now for radius apply Bernoulli's theorem at hole 1 and 2

P_1+\rho gh_1=P_{atm}+\frac{1}{2}\rho v_1^2

P_2+\rho g6h_2=P_{atm}+\frac{1}{2}\rho v_2^2

if hole 1 is h distance below water surface then h_2=6h

and P_1=P_2=P_{atm}

Also v_1=\sqrt{2gh}

v_2=\sqrt{2g(6h)}

and Q=A_1v_1=A_2v_2

A=\pi r^2

thus \dfrac{r_1}{r_2}=\sqrt{\dfrac{v_2}{v_1}}

\dfrac{r_1}{r_2}=\sqrt{\dfrac{\sqrt{6h}}{\sqrt{h}}}

\frac{r_1}{r_2}=1.565

5 0
3 years ago
The vertical normal stress increase caused by a point load of 10 kN acting on the ground surface at a point 1m vertically below
Tomtit [17]

Answer:

(b) 4.775 kN

Explanation:

see the attached file

8 0
2 years ago
What casues leaves to change color in autam
Furkat [3]

Answer: Chlorophyll Breaking down.

Explanation: When it starts to get cooler the chlorophyll breaks down causing the pretty green color to change to brown gold and orange.

3 0
2 years ago
Read 2 more answers
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