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Travka [436]
3 years ago
12

What is the best name for the molecule below? (2 points)

Chemistry
2 answers:
Irina-Kira [14]3 years ago
8 0

Answer: 4-ethyl-1-heptene

Explanation: The IUPAC nomenclature follows following rules

1. The longest carbon chain is chosen which must include the functional groups, double and triple bonds.

2. The numbering of the chain starts from the end such that the functional group or the double or triple bond gets the lowest number.

3. The carbons which do not get any number are called as substituents.

The name starts with the number of the carbon bearing the substituent, followed by the name of the substituent. Thus 4-propyl. Then the word root is written which is the number of carbons in the longest chain. Thus it is hept. Then the suffix is the number and name of the functional group or double and triple bond. Thus 1-ene.

The name is 4-ethyl-1-heptene.


Levart [38]3 years ago
4 0
Given:

A compound with:

Number of carbon atoms = 9
Number of double bonds = 1 
A double bond between 5th and 6th carbon
A propyl group (CH2CH2CH3) branching off the 3rd carbon from the left

Try to illustrate the given and observe the formation of the atoms. Now, follow the correct IUPAC naming system. The name of the compound is 

4-propyl-1-hexene

Count from the right to the left, the double bond is between the 1st and 2nd carbon, thus, 1-hexene. The propyl branches out the 4th carbon from the right, thus 4-propyl. 


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To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign. 

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3 years ago
In Lab 10 you make a stock solution of salicylic acid, and then four dilutions. The stock solution is made by diluting 5.00 ml o
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Answer:

Stock  solution =  1.25 *10^-3 M

Dilution 1 = 5*10^-4 M

Dilution 2= 3.75 * 10^-4 M

Dilution 3 = 2.5 *10^-4 M

Dilution 4 = 1.25 *10^-4 M

Explanation:

<u>Step 1:</u> Data given

The stock solution is made by diluting 5.00 ml of 1.250 x 10-2 M salicylic acid in 50.00 mL of solution.

<u>Step 2</u>: Calculate the concentration of the stock solution:

M1*V1 = M2*V2

⇒ with M1 = the initial concentration = 1.250 *10^-2 M

⇒ with V1 = 5 mL = 5*10^-3 L

⇒ with M2 = TO BE DETERMINED

⇒ with V2 = 50 mL = 50 *10^-3 L

M2 = (M1*V1)/V2

M2 = (1.250 *10^-2 * 5*10^-3 L) / 50 *10^-3

M2 = 0.00125 M = 1.25 *10^-3 M

<u>Step 3:</u> Calculate dilution 1

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 *10^-3)/(25*10^-3L)

M2 = 0.0005 M = 5*10^-4 M

<u>Step 4</u>: Calculate dilution 2

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 * 7.5*10^-3)/(25*10^-3)

M2 = 0.000375 M = 3.75 * 10^-4 M

<u>Step 5:</u> Calculate dilution 3

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 5*10^-3) /(25*10^-3)

M2 = 0.00025 M = 2.5 *10^-4 M

<u>Step 6</u>: Calculate dilution 4

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 2.5*10^-3)/(25*10^-3)

M2 = 0.000125 M = 1.25 *10^-4 M

5 0
3 years ago
10 POINTS
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Aluminum is an element. Which best describes what makes up a sample of aluminum?
sp2606 [1]
I believe the answer is A.
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3 years ago
Read 2 more answers
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