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Travka [436]
3 years ago
12

What is the best name for the molecule below? (2 points)

Chemistry
2 answers:
Irina-Kira [14]3 years ago
8 0

Answer: 4-ethyl-1-heptene

Explanation: The IUPAC nomenclature follows following rules

1. The longest carbon chain is chosen which must include the functional groups, double and triple bonds.

2. The numbering of the chain starts from the end such that the functional group or the double or triple bond gets the lowest number.

3. The carbons which do not get any number are called as substituents.

The name starts with the number of the carbon bearing the substituent, followed by the name of the substituent. Thus 4-propyl. Then the word root is written which is the number of carbons in the longest chain. Thus it is hept. Then the suffix is the number and name of the functional group or double and triple bond. Thus 1-ene.

The name is 4-ethyl-1-heptene.


Levart [38]3 years ago
4 0
Given:

A compound with:

Number of carbon atoms = 9
Number of double bonds = 1 
A double bond between 5th and 6th carbon
A propyl group (CH2CH2CH3) branching off the 3rd carbon from the left

Try to illustrate the given and observe the formation of the atoms. Now, follow the correct IUPAC naming system. The name of the compound is 

4-propyl-1-hexene

Count from the right to the left, the double bond is between the 1st and 2nd carbon, thus, 1-hexene. The propyl branches out the 4th carbon from the right, thus 4-propyl. 


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nata0808 [166]

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a)  the mass of air = 8.24 grams

b) the mass of helium = 1.14 grams

c) the mass difference = 7.10 grams

Explanation:

Step 1: Data given

Volume of the tire = 860 mL

Total pressure = 120 psi

Temperature = 26°C

molar mass of air = 28.8 g/mol

Step 2:  Convert psi to atm

(

120 psi) (1 atm / 14.7 psi) = 8.163

Step 4: Calculate moles

PV = nRT

 ⇒ with P = the pressure = 8.163 atm

⇒ with V = the volume = 860 mL = 0.860 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the universal gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 26 °C = 299 Kelvin

n = (8163*0.860)/(0.08206*299)

n = 0.2861 moles of gas

Step 5: Calculate the mass of air in an air-filled tire.

Mass = moles * molar mass

Mass = (0.2861 moles of gas) (28.8 g/mol)  

Mass = 8.24 grams

Step 6: Calculate the mass of helium in a helium- filled tire.

mass of helium = 0.2861 moles of gas * 4 g/mol)  

mass of helium  = 1.14 grams

Step 7: What is the mass difference between the two?

Δmass=  8.24 grams -  1.14 grams

Δmass= 7.10 grams

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3 years ago
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