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ExtremeBDS [4]
3 years ago
5

Suppose you discovered a new element with 120 protons and 2 electrons in its outer lever. In what group does this new element be

long
Physics
2 answers:
Mars2501 [29]3 years ago
7 0

Answer:

This new element belongs to the group 2.

Explanation:

In the periodic table, the vertical columns are called groups (or families). The elements in the same group share similar chemical and physical properties.

One of these properties is the same amount of outer valence electrons.

For example, in the group 1 the elements have 1 outer valence electron (If we assume that the element is in a neutral state which is without electrical charges).

If this new element has 2 electrons in its outer level it will belong to the group 2. The group 2 is well-known as alkaline earth metals.

For example, the magnesium (Mg) and the calcium (Ca) belong to the group 2.

Lyrx [107]3 years ago
5 0
Assuming the 2 valence electrons are of the neutral state of the new element, the element would belong in Group 2, the Alkaline Earth Metals.
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The experimentation step of scientific inquiry involves _______.
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True of false metals like copper are sometimes used to fill cavities in teeth
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3 years ago
Monochromatic light falling on two very narrow slits 0.048mm apart. Successive fringes on a screen 5.00m away are 6.5cm apart ne
tino4ka555 [31]

Answer:

λ = 5.85 x 10⁻⁷ m = 585 nm

f = 5.13 x 10¹⁴ Hz

Explanation:

We will use Young's Double Slit Experiment's Formula here:

Y = \frac{\lambda L}{d}\\\\\lambda = \frac{Yd}{L}

where,

λ = wavelength = ?

Y = Fringe Spacing = 6.5 cm = 0.065 m

d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m

L = screen distance = 5 m

Therefore,

\lambda = \frac{(0.065\ m)(4.8\ x\ 10^{-5}\ m)}{5\ m}

<u>λ = 5.85 x 10⁻⁷ m = 585 nm</u>

Now, the frequency can be given as:

f = \frac{c}{\lambda}

where,

f = frequency = ?

c = speed of light = 3 x 10⁸ m/s

Therefore,

f = \frac{3\ x\ 10^8\ m/s}{5.85\ x\ 10^{-7}\ m}\\\\

<u>f = 5.13 x 10¹⁴ Hz</u>

5 0
3 years ago
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