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3 years ago

Which of the following represents a virtual image?

Physics

1 answer:

Sauron [17]3 years ago

7 0

Answer:

Explanation:

A virtual image is on the same side as the object, which by convention is drawn on the left side. So -di would represent a virtual image.

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A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of

34kurt

Answer:

The centripetal acceleration of the runner is $1.73\ m/s^2$ .

Explanation:

Given that,

A runner completes the 200 m dash in 24.0 s and runs at constant speed throughout the race. We need to find the centripetal acceleration as he runs the curved portion of the track. We know that the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

v is the velocity of runner

$v=\dfrac{200\ m}{24\ s}\\\\v=8.34\ m/s$

Centripetal acceleration,

$a=\dfrac{(8.34)^2}{40}\\\\a=1.73\ m/s^2$

So, the centripetal acceleration of the runner is $1.73\ m/s^2$ . Hence, this is the required solution.

5 0

3 years ago

Which of the following is not a characteristic of major depressive disorder?

Alex787 [66]

D chest tightness

I experienced these the past few days...

but hoped I helped ^_^

6 0

2 years ago

Read 2 more answers

You have a 2m long wire which you will make into a thin coil with N loops to generate a magnetic field of 3mT when the current i

Anni [7]

Answer:

radius of the loop = 7.9 mm

number of turns N ≅ 399 turns

Explanation:

length of wire L= 2 m

field strength B = 3 mT = 0.003 T

current I = 12 A

recall that field strength B = μnI

where n is the turn per unit length

vacuum permeability μ = $4\pi *10^{-7} T-m/A$ = 1.256 x 10^-6 T-m/A

imputing values, we have

0.003 = 1.256 x 10^−6 x n x 12

0.003 = 1.507 x 10^-5 x n

n = 199.07 turns per unit length

for a length of 2 m,

number of loop N = 2 x 199.07 = 398.14 ≅ 399 turns

since there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.

this length is also equal to the circumference of each loop

the circumference of each loop = $2\pi r$

0.005 = 2 x 3.142 x r

r = 0.005/6.284 = $7.9*10^{-4} m$ = 0.0079 m = 7.9 mm

8 0

3 years ago

What is the lowest mass that an object can have and still be a star?

CaHeK987 [17]

Answer:

The lowest mass that an object can have to be considered a star is 0.08 solar masses.

Explanation:

A star is get when it reaches the necessary temperature in its core to nuclear reaction began.

A Nuclear reaction is the fusion of lighter elements into heavier elements.

In stars there is an equilibrium between two forces, the force of gravity in the inward direction due to its own mass and the radiation pressure in the upward direction as a consequence of the nuclear reaction in its core, which is known as hydrostatic equilibrium.

Therefore, the mass of the star must be enough to the force of gravity act in the inward direction, which leads to the increase in pressure, density and of course temperature in the core, allowing the nuclear reaction to begin.

Hence, the lowest mass that an object can have to be consider a star is 0.08 solar masses.

5 0

3 years ago

A very long solenoid with a circular cross section and radius r1= 1.30 cm with ns= 260 turns/cm lies inside a short coil of radi

allochka39001 [22]

Answer:

0.00851 volts

Explanation:

radius r1= 1.30 cm with ns= 260 turns/cm

radius r2= 4.60 cm and Nc= 23 turns

constant rate from zero to Is= 1.90 A

time interval of 88.0 ms