F = focal lenght = 67.1 cm
u= distance between mirror and object = 16.76 cm
1/f = 1/v + 1/u
1/67.1 = -1/16.76 + 1/u
1/67.1 + 1/16.76 = 1/u
u = 13.41
Capacitor in series with a 100Ω resistor and a 18.0 mH inductor will give a resonance frequency of 1000 Hz is 1.38F
Resonance Frequency of a combination of Series LCR circuit is the frequency at which resonance is achieved in a circuit.
Resonance Frequency of a combination of Series LCR circuit is given by:
f = 1 / 2π
where, f is the resonance Resonance Frequency of a combination of Series LCR circuit
L is the Inductance of the inductor
C is the capacitance of the capacitor
Given,
f = 1000Hz
L = 18.0 mH = 0.018H
R = 100Ω
C = ?
On substituting the values in the above-mentioned formula:
1000 = 1 / 2π
2π = 0.001
On solving, C = 1.38 F
Hence, the capacitance of the given capacitor is 1.38F.
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Answer:
1.33
Explanation:
Using the formula for destructive interference since the two reflected ray light waves from eyeglass should be made to cancel each other ( destructive interference) and also refractive index of air less than the refractive index of the film and both are less than the refractive index of the glass meaning the both reflected rays from the air and film will experience a phase change
n film = ( m + 0.5) ( λ / 2t)
since 2 t = ( m + 0.5) ( λ / n film)
where m is an integer, λ is wavelength, and t is thickness and n film is the refractive index of film
for effectiveness m = 0
n film = ( 0.5) ( 480 ÷ (2 × 90 ) ) = 1.33
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Since the system itself is giving off heat, this is a
reduction in the internal energy.
heat = - 25,000 J
Since work is being done on the system, therefore it is
an additional energy to the system. Work is given as:
work = - P dV
work = - 1.50 atm (6 L – 12 L)
work = 9 L atm
Since it is given that 1 L atm is equivalent to 101.3 J,
therefore the total energy added is:
energy due to work = 9 L atm (101.3 J / 1 L atm)
energy due to work = 911.7 J
Therefore the total change in internal energy is the sum
of heat and energy due to work:
Change in internal energy = - 25,000 J + 911.7 J
Change in internal energy = - 24,088.3 J
<span>Therefore, approximately 24.1 kJ of energy is lost by the
system in the total process.</span>
<span>
</span>
<span>Answer:</span>
<span>-24.1 kJ</span>