All categories

3 years ago

4) Solve for x: 4(2x - 10) = 12x + 10

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

8 0

Answer:

x=-25/2

Step-by-step explanation:

ipn [44]3 years ago

4 0

<h3>Answer:</h3>

$x = - \frac{25}{2}$

Alternative forms:

$x = - 12 \frac{1}{2}, \: or \: x = - 12.5$

<h3>Step-by-step explanation:</h3>

$4(2x - 10) = 12x + 10 \\ first \: you \: need \: to \: distribute \\ \\ 8x - 40 = 12x + 10 \\ subtract \: 12x \: from \: both \: sides \\ \\ - 4x - 40 = 10 \\ add \: 40 \: from \: both \: sides \\ \\ - 4x = 50 \\ divide \: both \: sides \: by \: - 4 \\ \\ x = - \frac{25}{2}$

You might be interested in

The formula for the area of a trapezold with altitude k and bases m and n is A=k/2(m+n)

Ghella [55]

Answer:

$m=\frac{2A-kn}{k}$

Hence, option C is true.

Step-by-step explanation:

Given the expression

$A=\frac{k}{2}\left(m+n\right)$

Solving for 'm'

$A=\frac{k}{2}\left(m+n\right)$

Flip the equation

$\frac{k}{2}\left(m+n\right)=A$

Expanding by applying the distributive law: $a\left(b+c\right)=ab+ac$

$\frac{1}{2}km+\frac{1}{2}kn=A$

Add (-1)/2 × kn to both sides

$\frac{1}{2}km+\frac{1}{2}kn+\left(-\frac{1}{2}kn\right)=\left(-\frac{1}{2}kn\right)+A$

simplify

$\frac{1}{2}km=-\frac{1}{2}kn+A$

Divide both sides by k/2

$\frac{\frac{1}{2}km}{\frac{k}{2}}=\frac{-\frac{1}{2}kn+A}{\frac{k}{2}}$

$m=\frac{2A-kn}{k}$

Therefore,

$m=\frac{2A-kn}{k}$

Hence, option C is true.

7 0

2 years ago

X/3=-7<br><br> find the variable

rjkz [21]

Answer:

x=−21

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

I really need help please

Anna [14]

Answer:

a kite

Step-by-step explanation:

because the question asks what special quadrennial is formed by connecting the midpoints

8 0

3 years ago

Write the equation for the graphed function. I worked out y = 5 - 4 (x + 4)^2 but that isn't right. Any help would be appreciate

alexira [117]

Vertex form for a parabola with vertex (p,q) is

$y = a(x-p)^2 + q$

We have (p,q)=(-4,5) and another point (-3,2) so we can solve for <em>a:</em>

$2 = a(-3 - -4)^2 + 5$

$2 = a + 5$

$a = -3$

Putting it together,

Answer: $y = -3(x + 4)^2 + 5$

We could multiply that out if we like but I won't bother.

5 0

3 years ago

What is the mass of a copper (II) chloride sample if it contains 0.0344 moles of the compound?

ale4655 [162]

According to the valence number of copper(2+) and the same value for chlorine (1-) copper (II) chloride has the formula of CuCl2

The molar mass of copper is 0,0635 kg/mole and chlorine gas a molar mass of 0,035 kg/mole the compound will have a molar mass of ( 0,0635+2×0,035 )kg/mole=0,099kg/mole and 0,344 moles are equivalent in mass to 0,344×0,135 kg=0,046 kg

5 0

1 year ago