Answer:
I believe that it is the 2nd option.
Explanation:
My reasonings are because C4H10O has 7 isomers. In which 4 are alcohol and the other 3 are ether.
The first option is ethers, specifically ethoxyethane.
The third option is ethers, specifically 1-methoxypropane.
The fourth option is an alcohol, specifically 1- butanol.
Therefore, leads us to the 2nd option that it is NOT an isomer of C4H10O
Answer: Option (A) is the correct answer.
Explanation:
A weak acid is defined as a substance which dissociates partially into a solvent. This also means that most of the molecules of a weak acid solution remain insoluble in nature.
A solution in which solute particles completely dissociate into ions in a solvent is known as a strong electrolyte.
Whereas a solution in which solute particles partially dissociate into ions is known as a weak electrolyte.
A molecular compound is a covalent compound and as like dissolves like. So, molecular compounds are not soluble in polar solvent like water.
Therefore, we can conclude that the true statement is weak acid solution consists of mostly insoluble acid molecules.
Answer: I would go with D.
Explanation: Sorry if it is incorrect
Answers:
G. -; H. -; I. +
Step-by-step explanation:
ΔE = q + w
Anything going into the system is positive (+), and anything leaving the system is negative (-).
G. Cooling with expansion
q: Heat is leaving; q is -
w: The system is doing work on the surroundings. Energy is leaving the system. w is -.
ΔE is -.
H. Heating a little, expanding a lot
q: Heat is entering; q is +.
w: The system is doing work on the surroundings. Energy is leaving the system. w is -.
However, the expansion work is the major factor.
ΔE ≈ w. ΔE is -.
I. Endothermic, no expansion
q: Heat is entering; q is +.
w: No expansion. w = 0.
ΔE = q. ΔE is +.
Answer:
C₆H₆O
Explanation:
The given values are the percentage in mass of each element. Empirical formula is the simplest ratio of atoms presents in a molecule. Thus, the first we need to do is convert this percentage to mass using molar mass of each element:
<em>Moles C:</em>
76.57C * (1mol / 12g) = 6.38 moles C
<em>Moles H:</em>
6.43 * (1mol / 1g) = 6.43 moles H
<em>Moles O:</em>
17.0% * (1mol / 16g) = 1.06 moles O
Dividing each number of moles in the moles of O (The minimum number of moles. Used to obtain "The simplest ratio..."):
C = 6.38 moles C / 1.06 moles O = 6
H = 6.43 moles H / 1.06 moles O = 6
O = 1.06 moles O / 1.06 moles O = 1
That means empirical formula of phenol is:
<h3>C₆H₆O</h3>
