How many moles of CO2 are produced from the combustion of 5.25 moles of CH3OH?

Chemistry

1 answer:

iVinArrow [24]2 years ago

4 0

First, we write the reaction for CH3OH combustion

CH3OH+3/2O2--->CO2+2H2O

for 1 mole of methanol, we get 1 mole of CO2, therefore for 5,25 moles of methanol we will get 5,25 moles of CO2

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Using this equation, m1v2=m2v2 , calculate the diluted molarity of 100 mL of a 0.5 M solution when 50 mL of

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The molarity of the diluted solution is 0.33 M

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 0. 5 M

Volume of stock solution (V₁) = 100 mL

Volume of diluted solution (V₂) = 100 + 50 = 150 mL

<h3>Molarity of diluted solution (M₂) =? </h3>

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

0.5 × 100 = M₂ × 150

50 = M₂ × 150

Divide both side by 150

M₂ = 50 / 150

Therefore, the molarity of the diluted solution is 0.33 M

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