Answer:
balanced , balanced , unbalanced, unbalanced, balanced, balanced, unbalanced
Explanation: you're welcome
Answer:
1.7 m/s²
Explanation:
d = length of the ramp = 13.5 m
v₀ = initial speed of the skateboarder = 0 m/s
v = final speed of the skateboarder = 7.37 m/s
a = acceleration
Using the equation
v² = v₀² + 2 a d
7.37² = 0² + 2 a (13.5)
a = 2.01 m/s²
θ = angle of the incline relative to ground = 29.9
a' = Component of acceleration parallel to the ground
Component of acceleration parallel to the ground is given as
a' = a Cosθ
a' = 2.01 Cos29.9
a' = 1.7 m/s²
Answer:
see solution below
Explanation:
The given resistors are connected in series.
Equivalent resistance in series = 30 + 55 + 15
Equivalent resistance in series Rt = 100 ohms
Since the potential difference in the circuit = 36V
Get the current in the circuit first
I = V/Rt
I = 36/100
I = 0.36A
Get the voltage across 30ohms resistor;
V30 = 0.36 * 30
V30 = 10.8volts
Hence the voltage across the 30ohms resistor is 10.8volts
Get the voltage across 55ohms resistor;
V55 = 0.36 * 55
V55 = 19.8volts
Hence the voltage across the 55ohms resistor is 19.8volts
Get the voltage across 15ohms resistor;
V15 = 0.36 * 15
V15 = 5.4volts
Hence the voltage across the 15ohms resistor is 5.4volts
Answer:
The light used has a wavelenght of 4.51×10^-7 m.
Explanation:
let:
n be the order fringe
Ф be the angle that the light makes
d is the slit spacing of the grating
λ be the wavelength of the light
then, by Bragg's law:
n×λ = d×sin(Ф)
λ = d×sin(Ф)/n
λ = (3.2×10^-4 cm)×sin(25.0°)/3
= 4.51×10^-5 cm
≈ 4.51×10^-7 m
Therefore, the light used has a wavelenght of 4.51×10^-7 m.
F = ma
a = f/m
if f doubled , acc. will be doubled