Answer:
Explanation:
T₁ = 700 + 273 = 973 k
T₂ = 330 + 273 = 603 k
Theoretical efficiency = T₁ - T₂ / T₁
= (973 - 603) / 973
= .38 OR 38%
Operating efficiency = .79 x 38
= 30.02 %
Heat input Q₁ , Heat output to sink Q₂ , conversion into power = Q₁ - Q₂
given Q₁ - Q₂ = 1.3 x 10⁹ W
efficiency = Q₁ - Q₂ / Q₁
Q₁ - Q₂ / Q₁ = 30.02 / 100
100Q₁ - 100Q₂ = 30.02Q₁
69.98 Q₁ = 100Q₂
Q₁ = 1.429 Q₂
Putting this in the relation
Q₁ - Q₂ = 1.3 x 10⁹ W
1.429Q₂ - Q₂ = 1.3 x 10⁹ W
.429Q₂ = 1.3 x 10⁹
Q₂ = 3.03 x 10⁹W
= 3.03 GW.
Answer:
Explanation:
The magnitude of the force of a moving cahrge, in our case a proton, trought a magentic field is given by:
(1)
where:
q is the proton charge (
)
v is the proton velocity (
)
B is the magnetic field (B = 1.17 T)
Now, we just need to solve the equaton (1) for \theta.
But the force F = ma, then:
m is the mass of proton (
)
a is the acceleration (
)
I hope it helps you!
We generally use circuit breaker to avoid short circuit in the circuit.
Answer:
I see no eaquations?
It should be matter=constant
