Answer:
1.58×10E18
Explanation:
Since we have the reduction potentials we could make decisions regarding which one will be the anode or cathode. Evidently, bromine having the more positive reduction potential will be the cathode while the iodine will be the anode.
E°cell= 1.07- 0.53= 0.54 V
E°cell= 0.0592/n logK
0.54 = 0.0592/2 logK
logK= 0.54/0.0296
logK= 18.2
K= Antilog (18.2)
K= 1.58×10^18
Answer:
1. 25%
2. 1.25
3. 1
Explanation:
Be sure to look at the x and y axis to answer these questions. All you need to do is look at the graph.
- Hope that helps! Please let me know if you need further explanation.
It would be 4.2, hope this helps.
