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ioda
3 years ago
6

Smh why do people always have to use fake profile pictures? Its not like anyone is gonna judge you it isnt facebook its a websit

e to get help with homework.
Chemistry
1 answer:
agasfer [191]3 years ago
7 0
Seriously though
people love to do that stuff .-.

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A metallic conductor moving at a constant speed in a magnetic field may develop a voltage across it. this is an example of _____
marysya [2.9K]
A metallic conductor moving at a constant speed in a magnetic field may develop a voltage across it. This is an example of Motional emf
Hope this helps!
3 0
3 years ago
Identify the number and kinds of atoms present in a molecule of each compound. caffeine c8h10n4o2 iron iii sulfate fe2(so4)3
finlep [7]
This problem is very easy to answer. You simply have to look at the subscripts of each element of the compound.

1. For caffeine, which has a molecular formula of C₈H₁₀N₄O₂, it contains 8 atoms of Carbon, 10 atoms of Hydrogen, 4 atoms of Nitrogen and 2 atoms of Oxygen.

2. For Iron(III) Sulfate, which has a molecular formula of Fe₂(SO₄)₃, it contains 2 atoms of Iron, 3 atoms of Sulfur, and 12 atoms of Oxygen.
6 0
3 years ago
Consider a mystery compound having the formula MxTy. If the compound is not an acid, if it contains only two elements, and if M
valkas [14]

Answer:

d.) It is a binary molecular compound.

Explanation:

The compound in question has a formula M{x}T_{y}. The compound is not acidic in nature and the element 'M' is not a metal. This shows that the compound does not contain any metal. Based on the definition of a binary molecular compound as a compound comprising elements that are not metals. Therefore, the compound is obviously a binary molecular compound.

7 0
2 years ago
Read 2 more answers
Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
Nutka1998 [239]

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

7 0
3 years ago
When road contractors are laying cement,they first place a series of steel rods in a specific patterns. the they pour the cement
Anna11 [10]
The steel rods will enable the concrete to form without any bumps and it will add shape to the cement and strength, so no odd massive lumps are formed.

That is what I think anyways :)
3 0
2 years ago
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