1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
polet [3.4K]
3 years ago
5

Predict which one of the following compounds would be insoluble in water.

Chemistry
2 answers:
MrRa [10]3 years ago
6 0
CH4 is less polar molecule compared to others. Except CH4, all the 3 compounds are ionic in nature and hence soluble in water.

Hence CH4 is insoluble in water.

Hope this helps!!
quester [9]3 years ago
4 0
CH4 is insoluble in water 
You might be interested in
What is the variable that is changed by
denpristay [2]

Answer:

b. independent/manipulated variable

Explanation:

Independent/manipulated variable - refers to the variable that is changed by the scientist or an experimenter. Only one variable that is independent is required to ensure a fair test in an excellent experiment. As the independent variable is being changed by an experimenter or scientist, data is being recorded simultaneously as they are collected.

3 0
1 year ago
3 organisms that help prevent infections
love history [14]

Infection control is the discipline concerned with preventing nosocomial or healthcare-associated infection, a practical (rather than academic) sub-discipline of epidemiology. It is an essential, though often underrecognized and undersupported, part of the infrastructure of health care. Infection control and hospital epidemiology are akin to public health practice, practiced within the confines of a particular health-care delivery system rather than directed at society as a whole. Anti-infective agents include antibiotics, antibacterials, antifungals, antivirals and antiprotozoals.[1]

Infection control addresses factors related to the spread of infections within the healthcare setting (whether patient-to-patient, from patients to staff and from staff to patients, or among-staff), including prevention (via hand hygiene/hand washing, cleaning/disinfection/sterilization, vaccination, surveillance), monitoring/investigation of demonstrated or suspected spread of infection within a particular health-care setting (surveillance and outbreak investigation), and management (interruption of outbreaks). It is on this basis that the common title being adopted within health care is "infection prevention and control." (got from google

8 0
3 years ago
Calculate the ph of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions.
Makovka662 [10]

The pH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions is 13.5.

<h3>What is pH? </h3>

pH is defined as the concentration of the hydrogen bond which is released or gained by the species in the solution which depicts the acidity and basicity of the solution.

<h3>What is pOH? </h3>

pOH is defined as the concentration of the hydronium ion present in solution.

pOH value is inversely proportional to the value of pH.

pH value increases, pOH value decreases and vice versa.

Given,

Total H+ ions = 2.95 ×10^(-12)M

<h3>Calculation of pH</h3>

pH = -log[H+]

By substituting the value of H+ ion in given equation

= log(2.95× 10^(-12) )

= 13.5

Thus we find that the pH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions is 13.5.

learn more about pH:

brainly.com/question/12942138

#SPJ4

8 0
2 years ago
Balance the chemichal equation:<br> NH3+CuO➡️Cu+N2+H2O
Gala2k [10]
2NH3+3CuO➡️3Cu+N2+3H2O
4 0
2 years ago
Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol)
kolbaska11 [484]

Answer:

The amount of NaOH required to prepare a solution of 2.5N NaOH.

The molecular mass of NaOH is 40.0g/mol.

Explanation:

Since,

NaOH has only one replaceable -OH group.

So, its acidity is one.

Hence,

The molecular mass of NaOH =its equivalent mass

Normality formula can be written as:Normality=\frac{mass of solute NaOH}{its equivalent mass}  * \frac{1}{volume of solution in L} \\

Substitute the given values in this formula to get the mass of NaOH required.

2.5N=\frac{mass of NaOH}{40g/mol} *\frac{1}{1L} \\mass of NaOH=2.5N*40gmol\\                         =      100.0g

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g

8 0
2 years ago
Other questions:
  • Convert 32.56 km/hr into ft/hr
    12·1 answer
  • The lymphatic system collects<br> While in<br> the lymphatic system, the fluid<br> is called
    7·1 answer
  • (b) Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2+
    5·1 answer
  • The solid has a mass of 180 g. What is the den of the solid?
    6·1 answer
  • One of the governing laws of the universe is the thermodynamic law of entropy. Which choice best describes entropy?
    13·1 answer
  • Please solve this for points please dont just write random stuff<br><br> 40 points! and brainliest
    10·1 answer
  • Do you agree or disagree with the following statement:
    7·1 answer
  • the wind pushes a paper cup along the sand at a beach. the cup has a mass of 0.025 kg and accelerates at a rate of 5 m/s2. how m
    5·1 answer
  • What is the mass number of an oxygen isotope that has nine neutrons.
    11·1 answer
  • At 0 °C, some amount of energy is required to change 1 kg of water from a solid into a liquid. If you had a 2 kg piece of ice, w
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!